15 problems
Let be jointly intersective, meaning that for every there exists such that divides each of…
Let be a probability space, and let be two not necessarily commuting measure-preserving transformations. Let , and suppose that…
Multiple recurrence conjecture. This liminf is positive. Furthermore, if all the rational polynomials have degree and for for some…
Mean convergence conjecture. These averages converge in as . Furthermore, if all the rational polynomials have degree , then the conclusion holds for all…
Let and let be functions of polynomial growth. Assume that every non-trivial linear combination of satisfies ……
Let be the Hardy field under consideration, let have polynomial growth, and assume … for every and . Let…
Multiple recurrence conjecture. The set contains a pattern of the form
Let be a degree number field with ring of integers , and let be an -valued intersective polynomial. Finitary configuration conject…
Let be a number field with ring of integers . Let be distinct and nonzero. For an -system , an -valued intersective po…
Parallelogram conjecture. The admissible triple has the large intersections property if and only if forms a parallelogram.
Quadruple-recurrence conjecture. If , then does not have the large intersections property.
Non-ergodic failure conjecture. There exist a necessarily non-ergodic measure-preserving system , a set with , and…
Pair characterization conjecture. The pair has the large intersections property if and only if it is admissible.
Let be a prime, let , and let be distinct elements of . A tuple has the Khintchine property when it satisfies the recurrence property define…
General Structural Conjecture. Depending only on these data, there are finite families of pairs for , with and…