19 problems
Naive bilinear Kakeya conjecture. Let . For every and every pair of transversal families of Heisenberg -tubes…
maximal-function conjecture. For all and ,
-set dimension conjecture. If is an set, then
For an odd prime power , a Besicovitch set in is a subset containing a line in every direction. Finite-plane Besicovitch set conjecture. The smallest Besicovi…
Multiplicity-line conjecture. If is small, then there is some such that every point with lies on the line . Th…
Let be odd, and write and for the lines and in . A Besicovitch set is a set containing one…
Let the bilinear tube estimate in Theorem be understood with its stated exponent, and let the sharp exponent mean the smallest exponent for which that estimate holds. Sha…
Polynomial Wolff axioms conjecture. The following assertions should hold:
Discretized Kakeya conjecture. The following two assertions should hold:
Let , let be a strictly convex hypersurface, and let denote the maximal Kakeya--Nikodym estimate referred to in the source as equation (MKNE)…
The family of fractal Fourier restriction estimates. For every there is a constant such that
Fix a positive integer . Let be the infimum of the Minkowski dimension of a set containing a -term arithmetic progression with e…
A Besicitch set is a subset containing a unit line segment in every direction. For such a set, let , ,…
Guth–Zahl conjecture. Let . For every , there are a complexity and a constant such…
Maximal tubular incidence conjecture. Let be unit line segments in whose directions are -separated. Then there is a constant…
For , let be a family of -tubes in . Call the families transversal when, for each , every tube in points in a…
Direction-separated polynomial Wolff conjecture. Every set of tubes pointing in -separated directions satisfies the polynomial Wolff axioms; more precisely, it satisfies th…
Kakeya conjecture for the polynomial Wolff axioms. For every dimension , there is a complexity such that, whenever is a set of -tubes in …
Let be arbitrary polynomials. Consider the map … For each extension , let be t…