17 problems
Diagonal determination conjecture. The family of polynomials , , is completely determined by the Alexander polynomial of .
Higher-order determination conjecture. The value of is completely determined by the Alexander polynomial and the family of polynomials ,…
Let be an odd integer with . For each with , let be the suitably normalized generalized Alexander invariant of a long …
Let … be the Dean knot represented by the closed -braid … where and are nonzero integers with . Let be the Alexander polynomial of . Hir…
Let be a link with components, let be its Alexander polynomial, and let be an abelian repre…
Let be a knot, let be the coupling parameter, and let denote the unknot. Let be the Alexander polynomial evaluated at , and set … Let…
Perturbed Conway invariant positivity conjecture. If is a positive knot, then all coefficients of are non-positive.
Let be a hyperbolic L-space knot, let be its Seifert genus, and let be its braid index. Let denote its Alexander polynomial. The hyperbolic L-space knot Al…
Universal-invariant conjecture. The universal invariant associated to has the form
Alexander-invariant limit conjecture. For (respectively, ), there exist numbers , , and such that the sequence of random variables
Let be an amphicheiral knot, and let be its Alexander polynomial. Stoimenow's sign conjecture. The sign of the leading coefficient of is … The conjecture…
Let be an amphicheiral knot, and let denote its Alexander polynomial; equivalently, consider the leading coefficient of its Conway polynomial. Stoimenow's square lea…
Let be a virtual knot. Let denote the zeroth Alexander polynomial, and let denote the odd writhe of . The odd writhe conjecture. … The relationship…
Wheels-part Alexander conjecture. What remains of the wheels part of is precisely the multivariable Alexander polynomial.
Let be a knot with exterior , let for the peripheral torus , and let be the longitude direction. Let a regular point of…
Let be an -component link, and let … where corresponds to a meridian of . Suppose that is algebraically split and component-preservingly…
Let be a knot, and let be its Alexander polynomial. Define … Choose such that . Polynomial-growth conjecture.…