Matching Tag: 2-adic-analysis
For an irrational real number α = [ a 0 ; a 1 , a 2 , … ] \alpha=[a_0;a_1,a_2,\ldots] α = [ a 0 ; a 1 , a 2 , … ] , let B ( α ) = lim sup n → ∞ a n ( α ) B(\alpha)=\limsup_{n\to\infty}a_n(\alpha) B ( α ) = lim sup n → ∞ a n ( α ) , where a n ( α ) a_n(\alpha) a n ( α ) are its continued-fraction partial quotients. The…
For an irrational real number α = [ a 0 ; a 1 , a 2 , … ] \alpha=[a_0;a_1,a_2,\ldots] α = [ a 0 ; a 1 , a 2 , … ] , let M ( α ) = sup n ≥ 1 a n ( α ) M(\alpha)=\sup_{n\geq 1}a_n(\alpha) M ( α ) = sup n ≥ 1 a n ( α ) , where a n ( α ) a_n(\alpha) a n ( α ) are its continued-fraction partial quotients. The 2-adic…
Let 5 ≤ Δ ≤ 8 5\le\Delta\le8 5 ≤ Δ ≤ 8 and e ≥ 5 e\ge5 e ≥ 5 . For j ≥ 0 j\ge0 j ≥ 0 , define … For j > 0 j>0 j > 0 , j ≠ 2 e − 1 j\ne2^{e-1} j = 2 e − 1 , and any integer m m m , define … Auxiliary valuation conjecture. The quantities satisfy all the follo…
Let 5 ≤ Δ ≤ 8 5\le\Delta\le8 5 ≤ Δ ≤ 8 , 0 ≤ m < 2 e − 1 0\le m<2^{e-1} 0 ≤ m < 2 e − 1 , and e ≥ 4 e\ge4 e ≥ 4 . If … then the difference-valuation conjecture. For every d ≥ 0 d\ge0 d ≥ 0 , … This is presented as a reduction step toward the one-zero c…
Let 5 ≤ Δ ≤ 8 5\le\Delta\le8 5 ≤ Δ ≤ 8 , let z Δ , ℓ ∈ Z 2 z_{\Delta,\ell}\in\mathbb Z_2 z Δ , ℓ ∈ Z 2 be the two zeros of P Δ P_\Delta P Δ indexed by ℓ ∈ { 0 , 1 } \ell\in\{0,1\} ℓ ∈ { 0 , 1 } , and let ε Δ , ℓ \varepsilon_{\Delta,\ell} ε Δ , ℓ be 2 2 2 for…
Let P n ( x ) P_n(x) P n ( x ) denote the partial Stirling function, let ν \nu ν be the 2-adic valuation, and let o ( n ) = n / 2 ν ( n ) \operatorname{o}(n)=n/2^{\nu(n)} o ( n ) = n / 2 ν ( n ) be the odd part of n n n . For integers e e e and…
Let x ∈ Z 2 x\in\mathbb Z_2 x ∈ Z 2 be a finite element, and let i 0 i_0 i 0 and d d d be positive integers such that x i 0 = 0 x_{i_0}=0 x i 0 = 0 and x i + d = x i x_{i+d}=x_i x i + d = x i for all i ≥ i 0 i\ge i_0 i ≥ i 0 , with 2 i + d ≤ x 2^{i+d}\le x 2 i + d ≤ x . Define … the…
Let x ∈ Z 2 x\in\mathbb Z_2 x ∈ Z 2 have binary digits x i ∈ { 0 , 1 } x_i\in\{0,1\} x i ∈ { 0 , 1 } , so that x = ∑ i ≥ 0 x i 2 i x=\sum_{i\ge0}x_i2^i x = ∑ i ≥ 0 x i 2 i . Suppose that, for some d ≥ 2 d\ge2 d ≥ 2 and i 0 ≥ 0 i_0\ge0 i 0 ≥ 0 , x i + d = x i x_{i+d}=x_i x i + d = x i for all i ≥ i 0 i\ge i_0 i ≥ i 0 . The eventu…