The square-sequence conjecture for L(A∞)L(\mathcal{A}^\infty)L(A∞)
Let Θ∞=ΘL(Γ∞,R)\Theta^\infty=\Theta^{L(\Gamma^\infty,\mathbb{R})}Θ∞=ΘL(Γ∞,R) and let L(A∞)L(\mathcal{A}^\infty)L(A∞) be the model generated by A∞\mathcal{A}^\inftyA∞. Square-sequence conjecture. … The claim is…