7 problems
There exist an absolutely continuous probability measure on and a number such that, for every pair of perpendicular lines in the plane, the four…
Ramos's conjecture. The triple is a solution if and only if
Soberón–Takahashi conjecture. Any finite absolutely continuous measures on can be simultaneously bisected by the chessboard coloring induced by or fewer…
Optimality conjecture. The result referred to as the fairy bread sandwich should be optimal for every such , , and permutation .
Kano's conjecture. There exists a curve in formed by horizontal and vertical segments, with at most turns, that bisects every measure.
Langerman's conjecture. For every such family of measures, there exists a set of hyperplanes whose induced chessboard coloring splits every measure into two equal parts.
Let a mass distribution in be a measure for which the bisection notion is defined. A set of hyperplanes bisects a mass distribution when, after orienting the hyp…