2 problems

Discreteness conjecture for commensurators of subgroups of lattices in $\mathrm{PSL}_2(\mathbb{R})$
Commensurator discreteness conjecture. The group $\operatorname{Comm}_{\mathrm{PSL}_2(\mathbb{R})}(\Phi(H))$ is discrete provided that $H\neq\Phi(H)$ . More generally,
openFrom paperscommensurators geometric-group-theory modular-groups
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7
Uniform equivariant quasi-isometry conjecture for geometrically rigid hyperbolic groups
Let $G$ be a geometrically rigid hyperbolic group. An abstract commensurator of $G$ is an isomorphism $\phi:H_1\to H_2$ between finite-index subgroups $H_1,H_2\leq G$ . A map…
openFrom paperscommensurators hyperbolic-groups quasi-isometries
0 responses
3

Discreteness conjecture for commensurators of subgroups of lattices in PSL2(R)\mathrm{PSL}_2(\mathbb{R})PSL2​(R)