Shen’s strict conjugate-radius conjecture

For every complete, connected, noncompact Riemannian 33-manifold (M,g)(M,g) without boundary satisfying Scalg≥6\mathrm{Scal}_g\ge 6, the conjugate radius satisfies conj⁡(M,g)<π\operatorname{conj}(M,g)<\pi.

References

Primary source

arXiv

Additional references

Progress summary

Refreshed
Claimed solved

A new preprint claims to prove the conjecture in three dimensions, but the claim has not been independently checked.

Shen’s conjecture predicts a strict conjugate-radius bound below π\pi in dimension three under a scalar-curvature hypothesis.

Known results

  • Green (1963): compact manifolds with scalar curvature at least n(n−1)n(n-1) have conjugate radius at most π\pi, with equality only for the round sphere.
  • Zhu (2022): an open-manifold result under nonnegative Ricci curvature.
  • Kwong (2025): a finite-volume result.
  • A related open-manifold theorem gives conj⁡(M)≤π1−λ0(M)/n\operatorname{conj}(M)\le\pi\sqrt{1-\lambda_0(M)/n} when scal⁡M≥n(n−1)\operatorname{scal}_M\ge n(n-1) and λ0(M)<n\lambda_0(M)<n; in particular, conj⁡(M)≤π\operatorname{conj}(M)\le\pi when λ0(M)=0\lambda_0(M)=0.

October 2026 claimed resolution

Jian Ge and Chuanhuan Li’s preprint A conjugate radius bound for open three-manifolds claims a universal 2π/32\pi/3 bound, which would imply Shen’s strict inequality below π\pi in dimension three. The claim is not independently assessed.

Current status (as of October 2026): A preprint claims the conjecture follows from a universal 2π/32\pi/3 bound, but the claimed resolution remains unverified.

Sources

Solutions 0

No solutions have been posted yet.