Kalmár elementary-function substitution-basis problem

Let E\mathcal{E} denote the class of Kalmár elementary functions, and let ⟨x+y,tdiv⁡(x,y),2x⟩\langle x+y,\operatorname{tdiv}(x,y),2^x\rangle denote the class of functions generated by substitution from addition, totalized integer division tdiv⁡\operatorname{tdiv}, and base-two exponentiation. The problem asks whether ⟨x+y,tdiv⁡(x,y),2x⟩=E\langle x+y,\operatorname{tdiv}(x,y),2^x\rangle=\mathcal{E}; equivalently, whether every Kalmár elementary function can be represented by a term using only these three operations.

References

Primary source

arXiv

Additional references

Progress summary

Refreshed
Claimed solved

An unrefereed preprint claims to disprove the conjecture by showing that the three allowed operations cannot generate all elementary functions.

The problem asks whether addition, integer quotient, and exponentiation by 22 generate all Kalmár elementary functions. It was posed as an open problem in a 2025 preprint.

Known results

  • Mazzanti (2002) and Marchenkov (2007) gave earlier substitution bases, including one using addition, remainder, squaring, and exponentiation.
  • Prunescu, Sauras-Altuzarra, and Shunia (2025) removed squaring: ⟨x+y, x mod y, 2x⟩=E\langle x+y,\ x\bmod y,\ 2^x\rangle=\mathcal{E}, with all three operations indispensable.
  • Their Problem 15 asked whether ⟨x+y, ⌊x/y⌋, 2x⟩=E\langle x+y,\ \lfloor x/y\rfloor,\ 2^x\rangle=\mathcal{E}; no solution was reported there.

October 2026 claimed disproof

Joseph M. Shunia's preprint On Integer-Division Bases for the Kalmár Elementary Functions claims a sparsity obstruction: the proposed basis cannot recover ⌊log⁡bx⌋\lfloor\log_b x\rfloor, integer remainder, or the input from bnb^n. If correct, this gives a negative answer to the open basis question, but the result is unrefereed and no independent assessment was found.

Current status (as of October 2026): The integer-division basis question has a claimed negative solution, but the sparsity argument is not independently verified; the remainder-based minimal basis is established in the cited preprint.

Sources

Solutions 0

No solutions have been posted yet.