H. Lee’s spanning-tree anticoncentration conjecture

For every fixed integer d≥3d\ge 3, there exists a constant cd>0c_d>0 such that, for every connected dd-regular graph GG on nn vertices and every tree TT on nn vertices, if TG\mathcal{T}_G is a uniformly random spanning tree of GG, then P(TG≅T)≤exp⁡(−cdn)\mathbb{P}(\mathcal{T}_G\cong T)\le \exp(-c_d n).

References

Primary source

arXiv

Additional references

Progress summary

Refreshed
Claimed solved

A new unrefereed preprint claims to prove Lee’s conjecture and sharpen it to an optimal asymptotic bound, but no independent verification was found.

H. Lee’s conjecture predicts that no particular tree can occur too often as the uniformly random spanning tree of a sufficiently dense connected graph, implying many non-isomorphic spanning trees. The new work also claims the sharp asymptotic estimate underlying this concentration statement.

Known results

  • Almost-regular graphs: Lee’s setting was previously known to satisfy exponential anticoncentration, with P(T≅T)≤e−Ω(n)\mathbb{P}(\mathcal{T}\cong T)\le e^{-\Omega(n)} for every nn-vertex tree TT (2026).

October 2026 claimed solution

On October 6, 2026, Beke, Bošković, Kamčev, and Wang reported an unrefereed preprint proving, for Δ(G)≤d\Delta(G)\le d, inj⁡(T,G)≤(d/e)neod(1)n\operatorname{inj}(T,G)\le (d/e)^n e^{o_d(1)n}, and deriving Lee’s conjecture for connected dd-regular graphs. A separate 2026 preprint claims the stronger minimum-degree conclusion P(T≅T)≤n−(1/2−on(1))(d−1)\mathbb{P}(\mathcal{T}\cong T)\le n^{-(1/2-o_n(1))(d-1)}.

Current status (as of October 2026): The conjecture has claimed proofs in unrefereed preprints, but the resolution remains unverified.

Sources

Solutions 0

No solutions have been posted yet.