Sylvester’s conjecture

For every prime p>3p>3 satisfying p≡4,7,8(mod9)p\equiv 4,7,8\pmod 9, there exist rational numbers x,y∈Qx,y\in\mathbb{Q} such that p=x3+y3p=x^3+y^3.

References

Primary source

arXiv

Additional references

Progress summary

Refreshed
Claimed progress

A new paper shortens the proof of one of the three cases, but the full conjecture remains unverified.

Sylvester’s conjecture predicts that every prime p>3p>3 with p≡4,7,8(mod9)p\equiv4,7,8\pmod 9 is a sum of two rational cubes. The record includes historical claims of a complete proof, but no independently assessed proof is supplied.

Known results

  • A 33-descent gives the expected rank pattern for the relevant elliptic curves.
  • For p≡4,7(mod9)p\equiv4,7\pmod 9 with 33 not a cube modulo pp, both pp and p2p^2 are sums of two rational cubes, with rank 11 (2017).
  • The unconditional p≡4,7(mod9)p\equiv4,7\pmod 9 result is claimed in a 2026 preprint, but remains unverified.

October 2026 shorter proof of the 88-case

Hongbo Yin gives a shorter proof of the already obtained p≡8(mod9)p\equiv8\pmod 9 case, using ordinary traces and a Kronecker congruence for modular functions. This simplifies one case but does not settle the remaining conjectural picture.

Current status (as of October 2026): The 88-case is reported as established and the 4,74,7 cases are claimed in recent work, but the complete conjecture has no independently verified resolution in the retrieved record.

Sources

Solutions 0

No solutions have been posted yet.