Co-sobriety of Hoare power spaces

Is it true that for every co-sober topological space X,X, the Hoare power space \PH(X)\PH(X) is co-sober? In particular, does this hold when XX is T2T_2 or metrizable?

Equivalent formulations 1Other wordings

Other statements of this same problem, merged from separate entries. Each is equivalent to the statement above — proving any one settles them all.

  1. Hoare-power/Scott-sobriety characterization

    For every T0T_0-space Y,\PH(Y)Y,\quad \PH(Y) is co-sober  ⟺  ΣO(Y)\iff\Sigma\mathcal{O}(Y) is sober..

    source: A countable metric space whose Hoare power space is not co-sober

References

Primary source

arXiv

Additional references

Progress summary

Refreshed
Claimed solved

An unrefereed preprint claims a countable metric counterexample, settling the preservation question negatively while awaiting verification.

The problem asks whether Hoare power spaces preserve co-sobriety. In October 2026, Xiaoquan Xu and Wei Ji reported a construction showing that this fails even for countable metrizable spaces.

October 2026 counterexample

Xu and Ji use a Ponomarev construction and a characterization via Scott sobriety to transfer a known countable T1T_1 counterexample to a countable metrizable space. The related Scott-sobriety question is also answered negatively: the cited work states that ΣO(Q)\Sigma\mathcal{O}(\mathbb{Q}) is not sober and uses a retract argument to transfer non-sobriety.

Current status (as of October 2026): A preprint claims the co-sobriety-preservation question is settled negatively, including for countable metrizable spaces, but the result remains unverified.

Sources

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