Cañete–Miranda Jr–Vittone planar strip isoperimetric conjecture

Let SS be a horizontal strip in R2\mathbb{R}^2, and let the density be ρ(x)=1\rho(x)=1 on SS and ρ(x)=λ>1\rho(x)=\lambda>1 on R2∖S\mathbb{R}^2\setminus S. For every λ>1\lambda>1 and every admissible four-arc region EE, there should exist an admissible three-arc region FF such that ∫Fρ dx=∫Eρ dx\int_F\rho\,dx=\int_E\rho\,dx and Pρ(F)<Pρ(E)P_\rho(F)<P_\rho(E), where PρP_\rho denotes weighted perimeter. Equivalently, no four-arc region can be isoperimetric when a three-arc competitor with the same weighted area is available.

References

Primary source

arXiv

Additional references

Progress summary

Refreshed
Claimed solved

A new unrefereed preprint claims to settle the conjecture for every allowed density contrast, but the claim has not been independently verified.

Cañete, Miranda Jr., and Vittone posed the conjecture in 2009 for a planar strip whose density is 11 inside the strip and λ>1\lambda>1 outside it.

Known results

  • Cañete, Miranda Jr., and Vittone (2009): the first candidate family is optimal for v≤πv\leq\pi.
  • For π<v≤v0\pi<v\leq v_0, the second candidate family is optimal, with v0>πv_0>\pi.
  • For v0≤v≤v1v_0\leq v\leq v_1, the third or fourth candidate family is optimal; for v≥v1v\geq v_1, the third is optimal.
  • The fourth family never occurs when λ≥4/π\lambda\geq4/\pi, settling the conjectured classification in that range.

September 2026 claimed resolution

Skilyn Leon, Rosa Pavlak, Evelyn Pulla, and Xi Sisi Shen’s preprint A comparison theorem for the planar strip isoperimetric problem claims a reduction valid for every λ>1\lambda>1, with an explicit positive perimeter gap, and therefore claims the full conjecture is settled. This is a newly posted, unrefereed claim with no independent verification reported in the retrieved sources.

Current status (as of September 2026): The conjecture is classically settled for λ≥4/π\lambda\geq4/\pi and claimed settled for all λ>1\lambda>1 by a new unverified preprint; the remaining general claim is not independently confirmed.

Sources

Solutions 0

No solutions have been posted yet.