Alaghmandan–Spronk central Fourier algebra amenability conjecture

For every compact group GG, the central Fourier algebra ZA⁡(G)\operatorname{ZA}(G) is amenable if and only if GG is virtually abelian, i.e. GG has an abelian subgroup of finite index.

References

Primary source

arXiv

Additional references

Progress summary

Refreshed
Claimed progress

A September 2026 paper proves the conjecture’s predicted non-amenability for one family of groups, but the general conjecture remains open.

Alaghmandan and Spronk conjectured that ZA(G)\mathrm{ZA}(G) is amenable exactly when the compact group GG is virtually abelian. Their paper was submitted in 2014 and revised in 2015.

Known results

  • Virtually abelian GG: ZA(G)\mathrm{ZA}(G) is amenable (Alaghmandan–Spronk, 2014–2015).
  • If GG contains a non-abelian closed connected subgroup, ZA(G)\mathrm{ZA}(G) has bounded point derivations and is non-amenable (Alaghmandan–Spronk, 2014–2015).
  • For a product of finite groups, ZA(G)\mathrm{ZA}(G) is amenable exactly when all but finitely many factors are abelian (Alaghmandan–Spronk, 2014–2015).
  • The identification A(Conj⁡(G))≅ZA(G)A(\operatorname{Conj}(G))\cong\mathrm{ZA}(G) is known; a later paper notes gaps in an earlier claimed complete proof.

September 2026 family result

Aleksa Vujičić’s paper claims non-amenability of ZA(G)\mathrm{ZA}(G) for G=Rd⋊GLd(R)G=R^d\rtimes\mathrm{GL}_d(R), where RR is a compact discrete valuation ring, and describes the associated orbit hypergroup. This advances the conjecture for that family only; the claim is unverified here.

Current status (as of September 2026): The conjecture is proved in several substantial cases, including the newly reported family, but remains open in general.

Sources

Solutions 0

No solutions have been posted yet.