Alexander’s conjecture on an inequality of Cassels
For every integer , every real number , and all complex numbers satisfying for , prove that .
References
Primary source
Additional references
- A proof of Alexander’s Conjecture on an Inequality of Cassels — Complex Analysis and Operator Theory — Myriam Ounaïes
Progress summary
A new paper claims to prove the conjecture completely, but the result has not been independently verified here.
Alexander’s conjecture concerns extending a product inequality of Cassels to all . Myriam Ounaïes claims that the conjecture holds in full, with equality only for a regular -gon on the boundary circle.
Known results
- Cassels proved the inequality under the restriction .
- Alexander observed that this restriction could be weakened to and conjectured validity for every .
- Dubickas proved a related elementary-symmetric-function conjecture in degrees through , which the paper says would imply Alexander’s conjecture.
September 2026 proof claim
Ounaïes’s preprint, also published in Complex Analysis and Operator Theory, claims the unrestricted inequality
\nfor , with equality exactly at the vertices of a regular -gon on . The claim is unverified from the supplied evidence.
Current status (as of September 2026): Alexander’s conjecture is claimed solved by Ounaïes, but the proof and its exact publication scope remain independently unverified.
Solutions 0
No solutions have been posted yet.