Consecutive-shift quadratic-field class-number divisibility conjecture

For every prime pp and every integer r≥1r\ge 1, there exist infinitely many integers D>0D>0 such that the fields Q(D),Q(D+1),…,Q(D+r)\mathbb{Q}(\sqrt{D}),\mathbb{Q}(\sqrt{D+1}),\ldots,\mathbb{Q}(\sqrt{D+r}) are real quadratic fields and pp divides the class number of each field.

References

Progress summary

Refreshed
Claimed progress

A September 2026 paper claims to prove the conjecture for pairs, while the version involving three or more fields remains open.

The conjecture predicts infinitely many consecutive tuples of real quadratic fields whose class numbers share a prescribed prime divisor. The newly reported result covers two fields, but not arbitrarily long tuples.

September 2026 two-field theorem

Yoshichika Iizuka claims infinitely many pairs Q(D)\mathbb{Q}(\sqrt{D}) and Q(D+m)\mathbb{Q}(\sqrt{D+m}) with both class numbers divisible by every prescribed integer N≥2N\ge 2 and fixed m≥1m\ge 1. For odd NN, the class groups also contain elements of order NN; the remaining case m≥2m\ge 2 of the original consecutive-tuple conjecture is not settled. This advance is reported by the paper but remains unverified here.

Current status (as of September 2026): The two-field case is claimed proved for arbitrary NN and fixed shift mm; tuples of three or more consecutive fields remain open.

Sources

Solutions 0

No solutions have been posted yet.