Yang’s question on RC-positivity of tangent bundles

For every smooth projective complex manifold XX, is XX rationally connected if and only if its holomorphic tangent bundle TXT_X admits a smooth uniformly RC-positive Hermitian metric? In particular, the unresolved converse asks whether TXT_X uniformly RC-positive implies that XX is rationally connected.

References

Primary source

arXiv

Additional references

Progress summary

Refreshed
Claimed solved

A new unrefereed preprint claims to settle the question by proving that rational connectedness is exactly equivalent to the relevant positivity conditions.

Yang’s question asks whether rational connectedness can be characterized by RC-positivity, or uniform RC-positivity, of the holomorphic tangent bundle. Earlier literature described this as Yang’s Problem 4.15 and left the converse unresolved.

Known results

  • Yang’s results: uniform RC-positivity of TXT_X, or RC-positivity of every ∧pTX\wedge^pT_X, implies projectivity and rational connectedness.
  • Yang, 2018: for projective rationally connected XX, the dual tautological line bundle associated with TXT_X is uniformly RC-positive, but this does not give uniform RC-positivity of TXT_X itself.
  • Qing, Sun, and Zhou, 2025: established partial converse results and described them as a step toward Yang’s question.
  • A 2026 result: uniform weak RC-positivity of TXT_X implies projectivity and rational connectedness, without proving the full converse.

September 2026 claimed equivalence

Chenghao Qing, Hongzhao Sun, and Xiangyu Zhou’s preprint Uniform RC-positivity of tangent bundles asserts equivalence among rational connectedness, RC-positivity, and uniform RC-positivity, with applications to blow-ups and selected non-Kähler surfaces. This would settle Yang’s question, but the version identified in the scan is an unrefereed version 11 preprint.

Current status (as of September 2026): The full equivalence is claimed in an unrefereed preprint but is not independently verified; the earlier literature leaves the converse open.

Sources

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