Moreto’s conjecture on Sylow-subgroup character counts

For every finite group GG, every prime pp, and every Sylow pp-subgroup P∈Syl⁡p(G)P\in\operatorname{Syl}_p(G), let Irr⁡p(G)={χ∈Irr⁡(G):p∣χ(1)}\operatorname{Irr}_p(G)=\{\chi\in\operatorname{Irr}(G):p\mid\chi(1)\}. Then every subgroup chain NG(P)=H0<H1<⋯<Hk=GN_G(P)=H_0<H_1<\cdots<H_k=G satisfies k≤∣Irr⁡p(G)∣k\leq\lvert\operatorname{Irr}_p(G)\rvert.

References

Primary source

arXiv

Additional references

Progress summary

Refreshed
Claimed solved

A new paper reports a counterexample, so the conjecture appears false, but the result has not yet been independently verified.

Moreto’s conjecture asserts that, for a finite group GG, prime pp, and Sylow pp-subgroup PP, nn irreducible characters with pp-divisible degrees force every subgroup chain from NG(P)N_G(P) to GG to have length at most nn.

Known results

For ∣Irrp(G)∣=1|\mathrm{Irr}_p(G)|=1, NG(P)N_G(P) is maximal in GG.

Counterexample report, September 22, 2026

Gang Chen and Wenhua Zhao report a counterexample with p=3p=3, ∣Irrp(G)∣=2|\mathrm{Irr}_p(G)|=2, and lp(G)=3l_p(G)=3, using a group of order 26⋅3⋅72^6\cdot3\cdot7. Thus the conjectured bound fails. They also announce forthcoming positive results for supersolvable groups and some solvable groups. The paper says the construction was found with help from OpenAI’s GPT-6.

Current status (as of September 2026): A counterexample is claimed, but independent verification is outstanding; the conjecture is not established as false until that claim is checked.

Sources

Solutions 0

No solutions have been posted yet.