Ford–Green–Koukoulopoulos close-divisors and equal-subset-sums conjecture

For each fixed integer k≥2k\ge 2, define αk\alpha_k as the supremum of the real numbers aa such that, for almost every positive integer nn, there exist kk distinct divisors of nn contained in a multiplicative interval of relative length (log⁡n)−a(\log n)^{-a}. Independently include each positive integer ii in a random set A\mathbf A with probability 1/i1/i, and define βk\beta_k as the supremum of the real numbers c<1c<1 such that, as D→∞D\to\infty with probability tending to 11, the set A∩[Dc,D]\mathbf A\cap[D^c,D] contains kk distinct subsets having equal sums. The conjecture is that αk=βk1−βk\alpha_k=\frac{\beta_k}{1-\beta_k} for every fixed k≥2k\ge 2.

References

Primary source

arXiv

Additional references

Progress summary

Refreshed
Claimed solved

A September 2026 preprint claims to prove the conjecture, but the result has not been independently verified.

Ford, Green, and Koukoulopoulos conjectured an exact relation between close-divisor and repeated-subset-sum concentration exponents, namely αk=βk/(1−βk)\alpha_k=\beta_k/(1-\beta_k) for fixed k≥2k\ge 2. Their framework appeared in 2019 and was published in 2023.

Known results

  • Ford, Green, and Koukoulopoulos established the lower bound αk≥βk/(1−βk)\alpha_k\ge\beta_k/(1-\beta_k) and presented equality as a conjecture; their work also characterized βk\beta_k through an optimization problem.

September 2026 claimed proof

On September 22, 2026, Jianfeng Hou and Hongbin Zhao’s preprint Equal subset sums and close divisors reported the equality αk=βk/(1−βk)\alpha_k=\beta_k/(1-\beta_k), using flag refinement, entropy concavity, and a uniform approximate-subset-sum bound. A separate September 2026 preprint likewise claims the converse inequality and the conjecture’s proof, together with an entropy-threshold identity.

Current status (as of September 2026): The conjectured equality is claimed in recent arXiv preprints, but remains unverified; the earlier lower bound is established.

Sources

Solutions 0

No solutions have been posted yet.