Simonovits–Sós 3AP-intersecting-family conjecture

For every positive integer nn, let [n]={1,…,n}[n]=\{1,\ldots,n\} and let F⊆2[n]\mathcal{F}\subseteq 2^{[n]} be a family such that for every A,B∈FA,B\in\mathcal{F}, the intersection A∩BA\cap B contains a non-trivial three-term arithmetic progression; that is, there exist integers a,da,d with d≠0d\ne 0 and {a,a+d,a+2d}⊆A∩B\{a,a+d,a+2d\}\subseteq A\cap B. Then ∣F∣≤2n−3|\mathcal{F}|\le 2^{n-3}, and this bound is conjectured to be best possible.

References

Primary source

arXiv

Additional references

Progress summary

Refreshed
Claimed progress

A September 2026 paper reports the first nontrivial improvement toward the conjectured bound, but the conjecture remains unsettled.

The Simonovits–Sós conjecture predicts that a 3AP-intersecting family has maximum size 2n−32^{n-3}. The available report gives progress toward this bound but does not establish the conjectured sharp constant.

September 2026 development

Peter Keevash reports a uniform gap below one half for 3AP-intersecting families and extends the result to HH-intersecting families for bounded-codegree 33-graphs. This is described as the first nontrivial improvement toward the conjectured maximum 2n−32^{n-3}, but the claim is unverified here.

Current status (as of September 2026): A uniform gap below one half is claimed, while the sharp maximum 2n−32^{n-3} remains open.

Sources

Solutions 0

No solutions have been posted yet.