Gao’s conjecture on the invariant ν(G)

For every nontrivial finite abelian group GG, let d(G)\mathsf d(G) denote the maximum length of a zero-sum-free sequence over GG. Let ν(G)\nu(G) be the least integer ℓ\ell such that every zero-sum-free sequence TT over GG with ∣T∣≥ℓ|T|\geq \ell satisfies: the set of all nonzero elements of GG that are not sums of nonempty subsequences of TT is contained in a proper coset of a subgroup of GG. Gao's conjecture asserts that ν(G)=d(G)−1\nu(G)=\mathsf d(G)-1 for every nontrivial finite abelian group GG.

References

Primary source

arXiv

Additional references

Progress summary

Refreshed
Claimed solved

A September 2026 preprint claims to disprove Gao’s conjecture, but the alleged counterexample has not yet been independently verified.

Gao’s conjecture asserts that the zero-sum invariant satisfies ν(G)=d(G)−1\nu(G)=\mathsf{d}(G)-1 for every nontrivial finite abelian group. Before the latest claim, the equality was known only for several substantial families, while the general question remained open.

Known results

  • Cyclic groups and pp-groups: ν(G)=d(G)−1\nu(G)=\mathsf{d}(G)-1.
  • Groups of rank at most 22: the equality is established.
  • Further cases include ν(C22⊕C2n)=d(C22⊕C2n)−1\nu(C_2^2\oplus C_{2n})=\mathsf{d}(C_2^2\oplus C_{2n})-1 and, for odd n>70n>70, the analogous equality for C24⊕C2nC_2^4\oplus C_{2n}.
  • No group was previously known with ν(G)=d(G)\nu(G)=\mathsf{d}(G); the general conjecture was described as out of reach.

September 2026 claimed disproof

On September 15, 2026, a report linked Alfred Geroldinger, Guoqing Wang, and Wenkai Yang’s arXiv preprint On a classical zero-sum invariant II: Disproof of a long-standing conjecture, which claims a counterexample to Gao’s universal equality. The retrieved metadata does not specify the counterexample, and the preprint is unrefereed.

Current status (as of September 2026): Gao’s conjecture is subject to a claimed counterexample in an unrefereed preprint, so the universal equality is not yet independently verified as false; the established positive cases remain settled.

Sources

Solutions 0

No solutions have been posted yet.