Erdős–Sós question on the uniform Turán density of K4^(3)

Determine whether the uniform Turán density of the tetrahedron satisfies πu ⁣(K4(3))=12\pi_u\!\left(K_4^{(3)}\right)=\frac{1}{2}. Here K4(3)K_4^{(3)} is the complete 33-uniform hypergraph on 44 vertices, and πu(H)\pi_u(H) is the supremum of the real numbers dd such that, for every ε>0\varepsilon>0 and all sufficiently large nn, there exists an HH-free 33-uniform hypergraph GG on nn vertices for which every subset U⊆V(G)U\subseteq V(G) with ∣U∣≥εn|U|\geq\varepsilon n satisfies e(G[U])≥(d−ε)(∣U∣3)e(G[U])\geq(d-\varepsilon)\binom{|U|}{3}.

References

Primary source

arXiv

Additional references

Progress summary

Refreshed
Claimed solved

An unrefereed September 2026 preprint claims the exact answer is one half, changing the problem from open to apparently solved but not yet independently confirmed.

The Erdős–Sós question asks whether the uniform Turán density of K4(3)K_4^{(3)} equals 1/21/2. Until this announcement, the question was explicitly described as open, with 1/21/2 believed optimal.

Known results

  • Rödl’s construction gives the lower bound 1/21/2 for K4(3)K_4^{(3)}.
  • A 2024 palette theorem reduces uniform Turán densities to palette constructions, but does not establish the K4(3)K_4^{(3)} case.

September 2026 claimed solution

Matija Bucić’s arXiv preprint The uniform Turán density of the tetrahedron claims that the exact density is 1/21/2, resolving the Erdős–Sós question. The result is reported as unrefereed and remains unverified.

Current status (as of September 2026): The value 1/21/2 is claimed by a new unrefereed preprint, but independent verification is not recorded; the earlier lower bound and conjectural status are established.

Sources

Solutions 0

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