Thomas’s question on Borel unfriendly partitions

Let G=(X,E)G=(X,E) be a locally finite Borel graph on a standard Borel space XX. Does there always exist a Borel coloring c:X→{0,1}c:X\to\{0,1\} such that, for every x∈Xx\in X, the number of neighbors of xx having color different from c(x)c(x) is at least the number of neighbors having color c(x)c(x)? Equivalently, does every locally finite Borel graph admit a Borel unfriendly partition?

References

Primary source

arXiv

Additional references

Progress summary

Refreshed
Claimed solved

A September 2026 preprint claims to disprove the universal existence statement with a locally finite Borel graph having no unfriendly coloring, but the counterexample has not been verified.

Thomas’s question asks whether every locally finite Borel graph admits a Borel unfriendly partition.

Known results

  • Every bounded-degree Borel graph of subexponential growth has a Borel unfriendly coloring.
  • Measure-preserving Borel graphs with finite cost have almost-everywhere unfriendly colorings.
  • Before 2026, the general question was open, even for bounded-degree graphs.

September 2026 counterexample claim; Community submission (unverified)

On September 10, 2026, José de Jesús Pelayo-Gómez’s preprint Unfriendly partitions of locally finite Borel graphs claimed a counterexample: an unbounded-degree, hyperfinite, bipartite, one-ended graph with no Borel unfriendly coloring. It also claims positive results for maximum degree at most 44 under additional structural conditions. A submission dated September 12, 2026 argues for the same negative conclusion via an E0E_0 treeing, an odd-degree forest, and a finite-fibre blow-up, but this argument is unverified.

Current status (as of September 2026): The universal question is claimed to have a negative answer, but the counterexample and the accompanying community argument remain unverified; restricted positive cases do not settle the remaining problem.

Sources

Solutions 1

ProofBorel Unfriendly Partitions of Locally Finite Graphs: A Parity Obstruction and Finite-Fibre Blow-Up CounterexampleSee full solutionHide full solution

We present a complete proof architecture for a negative answer to the Borel unfriendly-partition problem. Starting from the tail-equivalence relation E₀ on the space of binary sequences with infinitely many 1s, we construct a closed, locally finite, one-ended treeing whose edges are generated by a coordinate-flip parent map. A parity argument rules out Borel proper 2-colourings. We then modify the tree to an odd-degree forest and perform a finite-fibre blow-up with carefully chosen odd multiplicities. The blow-up has the rigidity property that every unfriendly colouring is fibrewise constant and induces a proper colouring of the underlying forest. Hence a Borel unfriendly colouring of the blow-up would yield a forbidden Borel proper colouring of the E₀ treeing. The construction therefore gives a locally finite Borel graph with no Borel unfriendly partition.

  • 01_negative_borel_unfriendly_partition_theorem_harvard-1.pdf279,334 bytesOpen
  • 03_finite_fibre_majority_amplification_harvard-3.pdf273,614 bytesOpen
  • Borel_Unfriendly_Partitions_Final_Manuscript.pdf114,199 bytesOpen
  • 02_descriptive_set_theoretic_parity_obstruction_harvard-2.pdf267,595 bytesOpen