Bernhard–Jablan conjecture

For every knot KK, there exists a minimal-crossing diagram DD of KK and a crossing of DD such that changing that crossing produces a knot K′K' satisfying u(K′)=u(K)−1u(K')=u(K)-1, where uu denotes the unknotting number.

References

Progress summary

Refreshed
Claimed solved

A computational paper reports a concrete counterexample, so the conjecture is false, but the calculation has not been independently verified here.

The Bernhard–Jablan conjecture asserts that every knot has a minimal-crossing diagram whose one-crossing change reduces its unknotting number. Brittenham and Hermiller reported a counterexample, making this a negative-resolution problem.

Known results

  • Brittenham and Hermiller (2017): K13n3370K13n3370 has u(K13n3370)≤2u(K13n3370)\le 2, while its weak Bernhard–Jablan unknotting number is 33.
  • Their exhaustive computations identify K12n288K12n288, K12n491K12n491, K12n501K12n501, and K13n3370K13n3370 as obstructions; they were independently checked with Knotscape.

September 2026 computational report

On September 9, 2026, Computation of unknotting numbers: which knot breaks the Bernhard–Jablan Conjecture reported 2,5252,525 previously unknown unknotting numbers and exhibited 13n337013n3370 as a counterexample. This reinforces the negative claim but does not, in this scan, supply independent verification.

Current status (as of September 2026): The conjecture is reported false via 13n337013n3370, with no later repair found, but the computational resolution remains unverified in this report.

Sources

Solutions 0

No solutions have been posted yet.