Measure contraction property conjecture for Grushin spaces

For each α≥1\alpha\ge 1, let the α\alpha-Grushin plane be R2=Rx×Ry\mathbb{R}^{2}=\mathbb{R}_{x}\times\mathbb{R}_{y} equipped with Lebesgue measure and the sub-Riemannian structure generated by X=∂xX=\partial_x and Yα=∣x∣α∂yY_{\alpha}=|x|^{\alpha}\partial_y. Determine the sharp parameters (K,N)(K,N) for which it satisfies the measure contraction property MCP⁡(K,N)\operatorname{MCP}(K,N). The conjectured classification is that MCP⁡(K,N)\operatorname{MCP}(K,N) holds if and only if K≤0K\le 0 and N≥NαN\ge N_{\alpha}, where Nα=1+max⁡L>1(2α+1)L(L−1)2α+1+1N_{\alpha}=1+\max_{L>1}\frac{(2\alpha+1)L}{(L-1)^{2\alpha+1}+1}.

References

Primary source

arXiv

Progress summary

Refreshed
Claimed solved

A September 2026 unrefereed preprint claims to settle the conjecture and extend the sharp threshold beyond integer cases, but the claim has not been independently verified.

The problem concerns the measure contraction property for Grushin spaces, including the broader α\alpha-Grushin family. The latest preprint claims a complete classification and new sharp examples.

Known results

  • The standard Grushin plane with Lebesgue measure satisfies MCP(K,N)\mathrm{MCP}(K,N) if and only if K≤0K\leq 0 and N≥5N\geq 5 (2017).
  • Grushin half-planes satisfy MCP(K,N)\mathrm{MCP}(K,N) if and only if K≤0K\leq 0 and N≥4N\geq 4 (2017).
  • A May 2025 preprint gave a computation-free proof of the standard Grushin-plane result via its quotient relation to the Heisenberg group.

September 2026 claimed resolution

A September 2026 arXiv preprint, The measure contraction property on Grushin spaces, claims necessary and sufficient MCP(K,N)\mathrm{MCP}(K,N) conditions and an explicit sharp threshold for α\alpha-Grushin spaces, including noninteger curvature exponents. It therefore claims to resolve the conjecture, but remains unrefereed and unverified.

Current status (as of September 2026): The standard Grushin-plane and half-plane thresholds are established, while the broader α\alpha-Grushin classification is only claimed solved by an unrefereed preprint and remains unverified.

Sources

Solutions 0

No solutions have been posted yet.