Gromov’s filling area conjecture

Let MM be a compact connected orientable Riemannian surface with boundary, and suppose that its boundary is isometric, with respect to the induced distance in MM, to the circle of circumference 2π2\pi. Then Area⁡(M)≥2π\operatorname{Area}(M)\ge 2\pi.

References

Primary source

arXiv

Progress summary

Refreshed
Claimed progress

A new September 2026 lower-bound result narrows the possibilities but does not settle Gromov’s conjecture.

The conjecture asks whether every compact orientable Riemannian surface filling a circle of circumference 2π2\pi has area at least 2π2\pi. The full statement remains unresolved.

Known results

  • The conjecture is known for disk fillings and genus-11 fillings.
  • A discrete analogue yields Area⁡(M)≥34π2\operatorname{Area}(M)\ge \frac{\sqrt{3}}{4}\pi^2 for arbitrary compact Riemannian fillings, without an orientability assumption.
  • Systolic inequalities establish the conjectured bound for certain sufficiently high-genus fillings; these are restricted results, not a general proof.

September 2026 Fourier lower bound

A September 8, 2026 report describes a Fourier-based method claiming Area⁡(M)≥14ζ(3)/π≈5.35677\operatorname{Area}(M)\ge 14\zeta(3)/\pi\approx 5.35677 generally and Area⁡(M)>5.40154\operatorname{Area}(M)>5.40154 for orientable fillings of the circle of length 2π2\pi. This is a claimed advance, not a complete resolution.

Current status (as of September 2026): The conjecture remains open; disk and genus-11 cases and other restricted bounds are known, while the new Fourier estimates are claimed progress but are not independently verified here.

Sources

Solutions 0

No solutions have been posted yet.