Han–Xiong 1/2-conjecture

Let r∈Q>0r\in\mathbb{Q}_{>0} and k∈Z≥1k\in\mathbb{Z}_{\ge 1}. If Tr⁡Z ⁣(rk)q\operatorname{Tr}_{\mathbb{Z}}\!\binom{r}{k}_q denotes the integer-exponent part (the integer trace) of the Gaussian binomial coefficient with positive rational upper index, then the Han–Xiong conjecture asserts the coefficientwise inequality Tr⁡Z ⁣(rk)q⪯Tr⁡Z ⁣(1/2k)q\operatorname{Tr}_{\mathbb{Z}}\!\binom{r}{k}_q\preceq\operatorname{Tr}_{\mathbb{Z}}\!\binom{1/2}{k}_q, equivalently [qn]Tr⁡Z ⁣(rk)q≤[qn]Tr⁡Z ⁣(1/2k)q[q^n]\operatorname{Tr}_{\mathbb{Z}}\!\binom{r}{k}_q\le [q^n]\operatorname{Tr}_{\mathbb{Z}}\!\binom{1/2}{k}_q for every integer exponent nn.

References

Primary source

The Ramanujan Journal

Additional references

Progress summary

Refreshed
Claimed progress

New work proves substantial special cases and verifies many finite cases, but the Han–Xiong conjecture remains open in full.

The Han–Xiong conjecture asserts that the integer trace at r=12r=\frac12 coefficientwise dominates the corresponding trace for every positive rational rr and integer k≥1k\ge1. The original paper gives special cases and computational evidence, not a complete proof.

Known results

  • Han and Xiong: proved several special families, including integral and half-integral rr, and established the conjecture for all positive rational rr when k≤3k\le3.
  • Exact computation verifies all positive rational rr for 1≤k≤2001\le k\le200; computations for r=13r=\frac13 and r=14r=\frac14 reach k=150k=150.

September 2026 developments

A new manuscript proves a support-dominance theorem implying the conjecture for every rational r≥12r\ge\frac12, reduces the remaining problem to primitive parameters r=12mr=\frac1{2m}, and identifies r=14r=\frac14 as the first unresolved primitive case. Its all-kk conclusions are reported as formally verified by AxiomProver, but the full conjecture remains unproved. On September 8, 2026, George E. Andrews and Mohamed El Bachraoui published adjacent-pair estimates in The Ramanujan Journal; the supplied record gives no abstract, so their precise strength cannot be assessed.

Current status (as of September 2026): substantial special cases, a reduction to r=12mr=\frac1{2m}, and finite computations are available, while the all-kk conjecture remains open and the latest estimates do not indicate a complete resolution.

Sources

Solutions 0

No solutions have been posted yet.