Kauers–Koutschan 2023 conjecture on long increasing subsequences

Let b2n,nb_{2n,n} denote the number of permutations of length 2n2n that contain an increasing subsequence of length nn, and define B(z)=∑n≥0b2n,nznB(z)=\sum_{n\geq 0} b_{2n,n}z^n. The conjecture is that B(z)B(z) is D-finite; equivalently, the sequence (b2n,n)n≥0(b_{2n,n})_{n\geq 0} is P-recursive, so there exist polynomials p0(n),…,pr(n)p_0(n),\ldots,p_r(n), not all zero, such that ∑j=0rpj(n)b2(n+j),n+j=0\sum_{j=0}^r p_j(n)b_{2(n+j),n+j}=0 for all sufficiently large nn.

References

Primary source

arXiv

Progress summary

Refreshed
Claimed solved

A 2026 preprint claims to settle the conjecture about counting permutations with long increasing subsequences, but the result has not been independently verified.

Kauers and Koutschan posed the conjecture in 2023, concerning recurrence properties of permutation counts involving long increasing subsequences.

September 2026 preprint

The preprint claims two bivariate recurrences for an,ka_{n,k}, the number of permutations of length nn whose longest increasing subsequence has length kk, valid when n/2≤k≤nn/2\leq k\leq n. It then derives the conjectured recurrence for b2n,nb_{2n,n}, counting permutations of length 2n2n containing an increasing subsequence of length nn, and claims the associated D-finiteness conclusion in that range. No independent verification, error report, or retraction was found.

Current status (as of September 2026): Kauers–Koutschan's conjecture is claimed proved by the 2026 preprint, with the D-finiteness statement established only for n/2≤k≤nn/2\leq k\leq n; independent verification remains outstanding.

Sources

Solutions 0

No solutions have been posted yet.