Two-centre Birkhoff–Poritsky conjecture

Let Ω⊂R2\Omega\subset\mathbb{R}^2 be a bounded domain with real-analytic boundary containing the segment joining the two centres, and let BhB_h denote the billiard map on the fixed-energy phase space MhM_h, for h≥0h\ge 0. If ∂Ω\partial\Omega is not an ellipse confocal with the two centres, then every real-analytic function F ⁣:Mh→RF\colon M_h\to\mathbb{R} satisfying F∘Bh=FF\circ B_h=F is constant.

References

Primary source

arXiv

Progress summary

Refreshed
Claimed solved

A September 2026 preprint claims to prove the conjecture in the planar non-negative-energy setting, while showing chaotic behavior for non-integrable tables.

The conjecture asserts analytic rigidity for planar two-centre billiards: in the non-confocal case, every analytic billiard invariant should be constant in the relevant non-negative-energy regime. No proposer or original date is identified in the retrieved sources.

September 2026 analytic-rigidity claim

A preprint claims that, for every non-confocal C1C^1 table and non-negative energy, one can construct trajectories with prescribed sufficiently large winding itineraries, full-shift-type invariant sets, periodic trajectories, and arbitrarily high entropy. It also claims that every analytic billiard invariant is constant for real-analytic boundaries, which would settle the stated conjecture in this regime. The claim is unverified.

Current status (as of September 2026): The planar analytic-rigidity claim for non-confocal tables at non-negative energy is reported as proved but remains unverified; broader smooth or higher-dimensional analogues remain open.

Sources

Solutions 0

No solutions have been posted yet.