Compactness of the ∂̄-Neumann operator versus analytic discs in the boundary

For every n≥2n\ge 2 and every bounded pseudoconvex domain Ω⊂Cn\Omega\subset\mathbb{C}^n with smooth boundary, does the existence of a nonconstant analytic disc in the boundary, כלומר, a nonconstant holomorphic map f:D→bΩf:\mathbb{D}\to b\Omega, imply that the ∂ˉ\bar\partial-Neumann operator N1N_1 on (0,1)(0,1)-forms is noncompact?

References

Progress summary

Refreshed
Claimed solved

A new unrefereed preprint claims that compactness can coexist with an analytic disc in the boundary, overturning the expected obstruction.

The problem asks whether a boundary analytic disc necessarily prevents compactness of the ∂ˉ\bar{\partial}-Neumann operator N1N_1. A new construction claims a negative answer, including failure of Catlin’s Property (P)(P) and McNeal’s Property (P~)(\widetilde P) despite compactness.

Known results

  • The unrestricted question was described as open in 2017; noncompactness was proved in C3\mathbb{C}^3 under finite regular D’Angelo 22-type.
  • The answer is affirmative in C2\mathbb{C}^2; Fu and Straube proved it for bounded locally convexifiable domains.
  • For bounded domains with bounded intrinsic geometry, compactness of NqN_q is equivalent to absence of qq-dimensional analytic varieties in the boundary (2021).
  • In that geometric setting, compactness is also equivalent to McNeal’s condition (Pq)(P_q) (2021).

September 2026 claimed counterexample

On September 1, 2026, a report linked the preprint Analytic discs and compactness of the ∂ˉ\bar{\partial}-Neumann operator, which claims compactness of N1N_1 alongside a boundary analytic disc. If correct, this would refute the general obstruction and separate compactness from (P)(P) and (P~)(\widetilde P); the claim is unverified.

Current status (as of September 2026): A preprint claims the general question is settled negatively, but the counterexample and proof remain unverified; no independent verification or referee report was found.

Sources

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