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Erdős Problem #893 — If τ(n)\tau(n) counts the divisors of nn then let f(n)=∑1≤k≤nτ(2k−1).f(n)=\sum_{1\leq k\leq n}\tau(2^k-1). Does f(2n)/f(n)f(2n)/f(n) tend to a limit?

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If τ(n)\tau(n) counts the divisors of nn then let f(n)=∑1≤k≤nτ(2k−1).f(n)=\sum_{1\leq k\leq n}\tau(2^k-1). Does f(2n)/f(n)f(2n)/f(n) tend to a limit?

References

Primary source

ULAM AI, UnsolvedMath dataset, Erdős Problems set, revision b9437975f3c873f635a13c48f8b022f5ba80898a; CC BY 4.0.

Additional references

UnsolvedMath, Erdős Problems set, ULAM AI, licensed CC BY 4.0.

divisorsnumber-theory
InErdős Problems
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