Seymour’s second-neighborhood conjecture

For every finite oriented graph G=(V,A), there exists a vertex v∈V such that ∣N2(v)∣≥∣N1(v)∣, where N1(v)={x∈V:(v,x)∈A} and N2(v)={x∈V∖N1(v):∃y∈N1(v) with (y,x)∈A}.\text{For every finite oriented graph }G=(V,A),\text{ there exists a vertex }v\in V\text{ such that }|N_2(v)|\ge |N_1(v)|,\text{ where }N_1(v)=\{x\in V:(v,x)\in A\}\text{ and }N_2(v)=\{x\in V\setminus N_1(v):\exists y\in N_1(v)\text{ with }(y,x)\in A\}.

References

Primary source

arXiv

Progress summary

Refreshed
Claimed progress

A new manuscript claims meaningful progress in dense graphs, but the general conjecture remains open.

Proposed by Paul Seymour in 1990 and first published by Nathaniel Dean and Brenda J. Latka in 1995, the conjecture asserts that every finite oriented graph has a vertex whose second out-neighborhood is at least as large as its first. The tournament case is known as Dean's conjecture.

Known results

  • Fisher (1996) proved the tournament case; Havet and Thomassé (2000) gave a short median-order proof.
  • Kaneko and Locke (2001) proved the conjecture when the minimum out-degree is at most 66.
  • Lladó (2013) proved it for regular oriented graphs with out-degree rr and connectivity r−1r-1.
  • Cary (2019) proved it for certain Eulerian oriented graphs.

June–August 2026 claimed extensions

A June preprint claims the minimum-outdegree-77 case, which would force any counterexample to have minimum out-degree at least 88 and at least 1919 vertices. An August manuscript claims the dense case n≤2δ+2n\leq 2\delta+2, implying a lower bound of 1717 vertices unconditionally; it credits GPT-5 family models with the exploration and proof development. Neither claim resolves the unrestricted conjecture.

Current status (as of August 2026): The tournament and several restricted cases are settled, while the dense-case and minimum-outdegree-77 extensions remain claimed results and the unrestricted conjecture is open.

Sources

Solutions 0

No solutions have been posted yet.