Snashall–Solberg conjecture

For every finite-dimensional associative algebra AA over a field KK, the quotient of its Hochschild cohomology ring by the ideal of nilpotent elements is a finitely generated KK-algebra; equivalently, HH(A)/G(N)\nobreak\operatorname{HH}^{*}(A)/\mathcal{G}(\mathcal{N}) is finitely generated, where N\mathcal{N} denotes the nilpotent elements and G(N)\mathcal{G}(\mathcal{N}) the ideal they generate.

Progress summary

Solved

A new unverified paper claims the conjecture fails even for highly symmetric algebras, while an earlier example had already shown failure in general.

The Snashall–Solberg conjecture proposed finite generation for Hochschild cohomology of finite-dimensional algebras. Its original form is already known to fail, and a new paper claims a counterexample that is both selfinjective and symmetric.

Known results

  • In characteristic 22, the one-point extension B=Γ[M]B=\Gamma[M], with Γ=K(Z2×Z2)\Gamma=K(\mathbb{Z}_{2}\times\mathbb{Z}_{2}) and M=KZ2M=K\mathbb{Z}_{2}, was identified as an initial counterexample to the original finite-generation conjecture (Psaroudakis, 2016).
  • The refined question of whether HH(A)/G(N)\operatorname{HH}^{*}(A)/\mathcal{G}(\mathcal{N}) is finitely generated was left open (Psaroudakis, 2016).

August 2026 symmetric counterexample

Edward L. Green and S. O. Ivanov claim a selfinjective, symmetric counterexample, extending the failure beyond nonsymmetric algebras. The claim is currently unrefereed and has no independent verification in the retrieved sources.

Current status (as of August 2026): The original conjecture is contradicted by a known nonsymmetric example, while the claimed selfinjective symmetric counterexample remains unverified and the refined quotient-finiteness question remains open.

Sources
Sources & referencesView supporting material

Primary source

arXiv

Additional references

Solutions 0

No solutions have been posted yet.