Erdős problem 647

Determine whether there exists an integer n>24n>24 such that max⁡1≤m<n(m+τ(m))≤n+2\max_{1\le m<n}\bigl(m+\tau(m)\bigr)\le n+2, where τ(m)\tau(m) denotes the number of positive divisors of mm. Equivalently, the conjecture asserts that no such nn exists.

Equivalent formulations 1Other wordings

Other statements of this same problem, merged from separate entries. Each is equivalent to the statement above — proving any one settles them all.

  1. Least-common-multiple formulation

    Define M(n,k)=lcm⁡(n+1,n+2,…,n+k)M(n,k)=\operatorname{lcm}(n+1,n+2,\ldots,n+k). Determine whether there exist integers m,n,km,n,k with m≥n+km\ge n+k such that M(n,k)=M(m,k)M(n,k)=M(m,k).

    source: Background supplied with the source

References

Primary source

arXiv

Additional references

Progress summary

Refreshed
Claimed progress

A new computer-checked certificate verifies only a finite range of cases, so the conjecture remains open.

Erdős problem 647 asks whether the least common multiples of two separated blocks of consecutive integers can ever coincide: M(n,k)=M(m,k)M(n,k)=M(m,k) with m≥n+km\ge n+k. Erdős posed the problem in the context of his 1979 work; the main entry still lists it as open.

Known results

  • Thue–Siegel implies that, for fixed kk, only finitely many pairs (m,n)(m,n) satisfy the equality.
  • Erdős recorded the known examples M(4,3)=M(13,2)M(4,3)=M(13,2) and M(3,4)=M(19,2)M(3,4)=M(19,2).
  • A related 2025 paper reports that the equivalent divisor-function formulation remains beyond its methods.

August 2026 kernel certificate

David Turean’s certificate checks a finite exclusion range end to end in Lean, strengthening confidence in that computational portion. It remains far below the prior non-kernel computational frontier and does not settle the conjecture. A January 2026 record also labels an AI-involving proof attempt incorrect.

Current status (as of August 2026): A finite exclusion range is kernel-verified, but the full conjecture and any possible exceptional cases remain open.

Sources

Solutions 0

No solutions have been posted yet.