The chemical antiregular graph conjecture for total σ\sigma-irregularity

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Let GG range over chemical graphs, and let σtf(n)\sigma_t^{f(n)} denote the total σ\sigma-irregularity with the weight function f(n)f(n). The graphs described in Theorem~

arethegraphsunderconsideration.∗∗Chemicalantiregulargraphconjecture.∗∗ThesamegraphsasinTheorem are the graphs under consideration. **Chemical antiregular graph conjecture.** The same graphs as in Theorem~

have maximum value of σtf(n)\sigma_t^{f(n)} even if f(n)f(n) is a constant in the interval (0,1)(0,1).

The conjecture proposes that the extremal graphs identified for the chemical-graph setting remain extremal when the weight function is any constant between 00 and 11, rather than only the previously considered choice. Its status is not resolved in the supplied source context.

References

Primary source

Martin Knor, Riste Škrekovski, Slobodan Filipovski and Darko Dimitrov, “Extremizing antiregular graphs by modifying total σ-irregularity”, arXiv:2411.01530 (2024).

Progress summary

Refreshed
Claimed progress

A reader has proposed a seven-vertex counterexample, but nobody has independently checked it, so the conjecture remains unsettled.

Knor, Škrekovski, Filipovski, and Dimitrov posed the conjecture in 2024: the chemical-graph extremizers from Theorem 9 should remain optimal for every constant weight in (0,1)(0,1).

Known results

  • For n≥7n\ge 7, Theorem 9 proves the stated extremal degree-multiplicity patterns when f(n)≤log⁡3 ⁣(3n23n2−8)f(n)\le \log_3\!\left(\frac{3n^2}{3n^2-8}\right) (Knor, Škrekovski, Filipovski, and Dimitrov, 2024).
  • The patterns are (k,k−1,k,k)(k,k-1,k,k) for n=4k−1n=4k-1, (k,k,k,k)(k,k,k,k) for n=4kn=4k, (k,k,k,k+1)(k,k,k,k+1) for n=4k+1n=4k+1, and (k,k+1,k,k+1)(k,k+1,k,k+1) or (k+1,k,k+1,k)(k+1,k,k+1,k) for n=4k+2n=4k+2.

Community submission (unverified)

Posted on August 26, 2026: A submitted argument claims that for n=7n=7 and f(n)≡12f(n)\equiv\tfrac12, a chemical graph with degree multiplicities (3,1,1,2)(3,1,1,2) has larger total σ\sigma-irregularity than the conjectured maximizers, which would disprove the conjecture.

Current status (as of August 2026): The conjecture remains unsettled; the proposed counterexample for n=7n=7 is unverified.

Sources

Solutions 1

CounterexampleThis solution needs a summarySee full solutionHide full solution

A Counterexample to the Chemical Antiregular Graph Conjecture

For a chemical graph GG of order nn, define

σtf(n)(G)=∑{u,v}∈(V(G)2)∣dG(u)−dG(v)∣f(n).\sigma_t^{f(n)}(G) = \sum_{\{u,v\}\in\binom{V(G)}2} \lvert d_G(u)-d_G(v)\rvert^{f(n)}.

Here a chemical graph is a finite connected simple graph with maximum degree at most 44.

The chemical antiregular graph conjecture (Conjecture 11 in the source paper) states that the graphs prescribed in Theorem 9 continue to maximize σtf(n)\sigma_t^{f(n)} when f(n)f(n) is any constant in the interval (0,1)(0,1). We disprove this statement for n=7n=7 and the constant function

f(n)≡12.f(n)\equiv \frac12.

Construction

Let GG have vertex set

V(G)={1,2,3,4,5,6,7}V(G)=\{1,2,3,4,5,6,7\}

and edge set

E(G)={{1,2},{1,3},{1,5},{1,6},{2,3},{2,4},{2,7},{3,4}}.\begin{aligned} E(G)=\{&\{1,2\},\{1,3\},\{1,5\},\{1,6\}, \{2,3\},\{2,4\},\\ &\{2,7\},\{3,4\}\}. \end{aligned}

The six edges

{1,2}, {1,3}, {1,5}, {1,6}, {2,4}, {2,7}\{1,2\},\ \{1,3\},\ \{1,5\},\ \{1,6\},\ \{2,4\},\ \{2,7\}

form a spanning tree of GG. Hence GG is connected. The listed edges are distinct unordered pairs of distinct vertices, so GG is simple. The degrees of vertices 1,2,…,71,2,\ldots,7, in that order, are

(4,4,3,2,1,1,1).(4,4,3,2,1,1,1).

In particular, Δ(G)=4\Delta(G)=4, so GG is a chemical graph. If aia_i denotes the number of vertices of degree ii, then

(a1,a2,a3,a4)=(3,1,1,2).(a_1,a_2,a_3,a_4)=(3,1,1,2).

Exact value of the invariant

For j∈{1,2,3}j\in\{1,2,3\}, let NjN_j be the number of unordered pairs of vertices whose degrees differ by jj. For any chemical graph with degree multiplicities (a1,a2,a3,a4)(a_1,a_2,a_3,a_4),

N1=a1a2+a2a3+a3a4,N2=a1a3+a2a4,N3=a1a4.\begin{aligned} N_1&=a_1a_2+a_2a_3+a_3a_4,\\ N_2&=a_1a_3+a_2a_4,\\ N_3&=a_1a_4. \end{aligned}

Pairs of equal-degree vertices contribute 00. Therefore, when f(n)=12f(n)=\tfrac12,

σt1/2=N1+N22+N33.\sigma_t^{1/2}=N_1+N_2\sqrt2+N_3\sqrt3.

For GG, the multiplicities (3,1,1,2)(3,1,1,2) give

(N1,N2,N3)=(6,5,6),(N_1,N_2,N_3)=(6,5,6),

and hence

σt1/2(G)=6+52+63.\sigma_t^{1/2}(G)=6+5\sqrt2+6\sqrt3.

Comparison with the conjectured maximizers

Since 7=4⋅2−17=4\cdot2-1, the degree multiplicities prescribed by Theorem 9 for order 77 are

(a1,a2,a3,a4)=(2,1,2,2).(a_1,a_2,a_3,a_4)=(2,1,2,2).

Let HH be any chemical graph with these multiplicities. Because σtf(n)\sigma_t^{f(n)} depends only on the vertex degrees and not on the adjacencies among the vertices, every such HH has the same value. Here

(N1,N2,N3)=(8,6,4),(N_1,N_2,N_3)=(8,6,4),

so

σt1/2(H)=8+62+43.\sigma_t^{1/2}(H)=8+6\sqrt2+4\sqrt3.

The exact difference is

σt1/2(G)−σt1/2(H)=(6+52+63)−(8+62+43)=−2−2+23.\begin{aligned} \sigma_t^{1/2}(G)-\sigma_t^{1/2}(H) &=(6+5\sqrt2+6\sqrt3)-(8+6\sqrt2+4\sqrt3)\\ &=-2-\sqrt2+2\sqrt3. \end{aligned}

This difference is strictly positive. Indeed, all terms below are positive, and therefore squaring preserves the direction of the relevant inequalities:

23>2+2  ⟺  12>(2+2)2  ⟺  12>6+42  ⟺  3>22  ⟺  9>8.\begin{aligned} 2\sqrt3>2+\sqrt2 &\iff 12>(2+\sqrt2)^2\\ &\iff 12>6+4\sqrt2\\ &\iff 3>2\sqrt2\\ &\iff 9>8. \end{aligned}

Consequently,

σt1/2(G)>σt1/2(H)\sigma_t^{1/2}(G) > \sigma_t^{1/2}(H)

for every order-77 chemical graph HH having the degree multiplicities prescribed by Theorem 9.

Conclusion

The function f(n)≡12f(n)\equiv\tfrac12 is constant and takes its value in (0,1)(0,1), but the graph GG above has strictly larger σtf(n)\sigma_t^{f(n)} than every graph in the class asserted by the conjecture to be maximizing. Therefore the chemical antiregular graph conjecture is false.

This does not contradict Theorem 9 itself. At n=7n=7, the hypothesis of that theorem requires

f(7)≤log⁡3 ⁣(147139)≈0.0509358,f(7)\leq \log_3\!\left(\frac{147}{139}\right) \approx 0.0509358,

whereas f(7)=12f(7)=\tfrac12. The counterexample instead disproves the conjectured extension of Theorem 9 to constants in (0,1)(0,1).

Optional exhaustive verification

The preceding exact comparison is already a complete disproof; no computer search is needed. As an independent check, all

2(72)=221=2,097,1522^{\binom72}=2^{21}=2{,}097{,}152

labeled simple graphs on seven vertices were enumerated. Exactly 859,130859{,}130 of them are connected and have maximum degree at most 44. At f(n)=12f(n)=\tfrac12, the maximum over these graphs is attained precisely at the degree-multiplicity vector

(3,1,1,2),(3,1,1,2),

with value

6+52+63.6+5\sqrt2+6\sqrt3.

Thus the displayed graph is globally optimal among all seven-vertex chemical graphs, although this stronger computational fact is not needed to refute the conjecture.

Reference

M. Knor, R. Škrekovski, S. Filipovski, and D. Dimitrov, “Extremizing antiregular graphs by modifying total σ\sigma-irregularity,” Applied Mathematics and Computation 490 (2025), Article 129199. doi:10.1016/j.amc.2024.129199; arXiv:2411.01530.