Thomas's trimness conjecture for Cambrian lattices

From papers

Let C(Gˉ)C(\bar G) be a Cambrian lattice associated with an oriented Dynkin diagram Gˉ\bar G of a finite reflection group. A lattice is trim if it has a left modular maximal chain and equally many atoms and join-irreducible elements. Thomas's conjecture. All Cambrian lattices are trim. The Cambrian lattices in types AA and BB are proved to be trim in the paper; the conjecture concerns the other finite reflection-group types, which were not yet well understood.

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Sources & referencesView supporting material

Primary source

Hugh Thomas, “An analogue of distributivity for ungraded lattices”, arXiv:math/0502278 (2005).

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