Better-balanced-pair inequality conjecture for the cd-index

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Let (m1,n1)(m_1,n_1) and (m2,n2)(m_2,n_2) be pairs of non-negative integers, where (m1,n1)(m_1,n_1) is strictly better balanced than (m2,n2)(m_2,n_2), meaning that the first pair is strictly closer to balance than the second in the sense used in the paper. Let LL, MM, and NN be lists. Better-balanced-pair inequality conjecture. Then

β(M,m1,L,n1,N)>β(M,m2,L,n2,N).\beta(M,m_1,L,n_1,N)>\beta(M,m_2,L,n_2,N).

This extends the preceding pairwise comparison to arbitrary lists inserted between and around the two entries; the source gives no resolution.

References

Primary source

Swapneel Mahajan, “The cd-index of the Boolean lattice”, arXiv:math/0211390 (2002).

Progress summary

Refreshed
Claimed solved

A reader-written calculation claims a counterexample disproves the conjecture, but no independent verification has appeared.

Mahajan formulated this extension of the balance conjecture for Boolean-lattice cdcd-coefficients and recorded it as Conjecture 4. It asserts that making the designated pair closer to balance strictly increases the coefficient, even with arbitrary surrounding lists.

Known results

  • Mahajan (2002): proved partial balance inequalities in Theorems 4 and 5.
  • Mahajan (2002): established related reverse-unimodality inequalities and characterized the maximum coefficient in each degree.
  • Ehrenborg and Readdy (2019): surveyed these results without resolving the arbitrary-list conjecture.

Posted attempt

A reader-written computation claims a counterexample in cdcd-monomial degree 2525, using (m1,n1)=(5,5)(m_1,n_1)=(5,5) and (m2,n2)=(4,6)(m_2,n_2)=(4,6), with surrounding lists (0)(0) and (0,7)(0,7). It reports the supposedly better-balanced case has the smaller coefficient, contradicting the conjectured strict inequality. The calculation has not been independently verified.

Current status (as of August 2026): An unverified complete counterexample claim is recorded, while Mahajan’s partial results are established and no independently verified proof or disproof is available.

Sources

Solutions 1

CounterexampleThis solution needs a summarySee full solutionHide full solution

The conjecture is false for cdcd-monomials of degree 2525.

Use the list notation

(a1,…,ar)=ca1dca2d⋯dcar,(a_1,\ldots,a_r)=c^{a_1}dc^{a_2}d\cdots dc^{a_r},

and take

M=(0),L=(0,7),N=∅,M=(0),\qquad L=(0,7),\qquad N=\varnothing,

together with

(m1,n1)=(5,5),(m2,n2)=(4,6).(m_1,n_1)=(5,5),\qquad(m_2,n_2)=(4,6).

Both pairs have sum 1010, and

∣5−5∣=0<2=∣4−6∣,|5-5|=0<2=|4-6|,

so (5,5)(5,5) is strictly better balanced than (4,6)(4,6). The conjecture therefore predicts

β(0,5,0,7,5)>β(0,4,0,7,6).(1)\beta(0,5,0,7,5)>\beta(0,4,0,7,6). \tag{1}

The coefficients can be computed directly from the established Lemmas 3.2 and 4.4 of the source. For every nonempty list a=(a1,…,ar)a=(a_1,\ldots,a_r), these give

β(a)=∑1≤i≤rai>0β(a1,…,ai−1,…,ar)+∑i=1r−1β(a1,…,ai−1,ai+ai+1+1,ai+2,…,ar),(2)\begin{aligned} \beta(a) ={}&\sum_{\substack{1\leq i\leq r\\a_i>0}} \beta(a_1,\ldots,a_i-1,\ldots,a_r)\\ &+\sum_{i=1}^{r-1} \beta(a_1,\ldots,a_{i-1},a_i+a_{i+1}+1, a_{i+2},\ldots,a_r), \end{aligned} \tag{2}

with initial condition β((0))=1\beta((0))=1. Every list on the right has degree one less than aa, where

deg⁡(a)=∑iai+2(r−1),\deg(a)=\sum_i a_i+2(r-1),

so (2) is a finite exact integer recursion.

Evaluating (2) gives

β(0,5,0,7,5)=1,287,894,857,340,\beta(0,5,0,7,5)=1{,}287{,}894{,}857{,}340,

whereas

β(0,4,0,7,6)=1,288,645,806,880.\beta(0,4,0,7,6)=1{,}288{,}645{,}806{,}880.

Thus

β(0,5,0,7,5)−β(0,4,0,7,6)=−750,949,540<0,\beta(0,5,0,7,5)-\beta(0,4,0,7,6) =-750{,}949{,}540<0,

which is the opposite of (1).

As an independent coefficient recurrence, Proposition 2 gives

Ψ(Br+1)=Ψ(Br)c+D(Ψ(Br)),D(c)=d,D(d)=cd,\Psi(B_{r+1})=\Psi(B_r)c+D(\Psi(B_r)), \qquad D(c)=d,\quad D(d)=cd,

with DD a derivation. Therefore b(∅)=1b(\varnothing)=1 and

b(w)=1{w ends in c}b(w with its last c removed)+∑d-positionsb(w with that d replaced by c)+∑cd-substringsb(w with that cd replaced by d).b(w) =\mathbf1_{\{w\text{ ends in }c\}}b(w\text{ with its last }c\text{ removed}) +\sum_{\text{$d$-positions}}b(w\text{ with that }d\text{ replaced by }c) +\sum_{\text{$cd$-substrings}}b(w\text{ with that }cd\text{ replaced by }d).

This separate recursion yields the same two values. Hence the more balanced pair gives a strictly smaller Boolean-lattice cdcd-coefficient, disproving the conjecture.