The free-rank conjecture for HOMFLYPT Yang–Baxter homology

Let R(m)R_{(m)} be the unital Yang–Baxter operator giving the HOMFLYPT polynomial on level mm, and let Hn(R(m))H_n(R_{(m)}) denote its homology. The free part of Hn(R(m))H_n(R_{(m)}) means its direct summand consisting of free kk-modules.

Free-rank conjecture. The rank of the free part of Hn(R(m))H_n(R_{(m)}) is 2m12^{m-1} for nm1n\geq m-1, while

rank(Hn(R(m)))=(m10)+(m11)++(m1n)\operatorname{rank}(H_n(R_{(m)}))=\binom{m-1}{0}+\binom{m-1}{1}+\cdots+\binom{m-1}{n}

for 0<nm10<n\leq m-1.

The source says that the displayed right-hand side was proved to be a lower bound for the rank, but does not state that equality was proved. Thus the full conjecture remains open on the supplied evidence.

Sources & referencesView supporting material

Primary source

Jozef H. Przytycki, “Path to homology of Yang-Baxter operators”, arXiv:2607.28626 (2026).

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