Lecture hall position conjecture for the Euler partition bijection

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Let λ=(λ1,λ2,…)\begin{aligned} \lambda=(\lambda_1,\lambda_2,\ldots)\end{aligned} be an odd partition, meaning that all its parts are odd, and suppose that its largest part occurs exactly rr times. Let π=φ(λ)\pi=\varphi(\lambda), where φ\varphi is the bijection under discussion. If πj\pi_j determines the lecture hall position, write

rπ≡πj(modmj),mj=πj−πj+1,rπ>0.r_\pi\equiv \pi_j\pmod {m_j},\qquad m_j=\pi_j-\pi_{j+1},\qquad r_\pi>0.

Lecture hall position conjecture. If π=φ(λ)\pi=\varphi(\lambda), then

r=rπ.r=r_\pi.

This conjecture is supported by substantial numerical evidence. It asserts that the multiplicity of the largest part of an odd partition is preserved as the corresponding lecture hall position under the bijection φ\varphi; no proof or resolution is given in the source.

References

Primary source

Andrew Y. Z. Wang and Lei Zhang, “Euler's partition theorem and lecture hall partition theorem”, arXiv:2607.16690 (2026).

Progress summary

Refreshed
Claimed solved

The conjecture remains unverified: a posted argument claims a complete proof, while the paper that introduced it only states it as a conjecture.

Wang and Zhang (2026) introduce the bijection from odd-part partitions to distinct-part partitions and formulate the conjecture that the largest-part multiplicity equals the associated lecture-hall position. Their paper presents it as an open conjecture supported by numerical evidence.

Posted attempt

A posted argument claims a complete proof for every odd partition. It combines the lecture-hall-length formula, the asserted descent relation, and a first-drop calculation to conclude r=rπr=r_\pi. The argument has not been independently verified.

Current status (as of August 2026): The conjecture has a complete-proof claim but no independent verification; absent validation, the mathematical problem remains open.

Sources

Solutions 1

ProofThis solution needs a summarySee full solutionHide full solution

Proof for every odd partition. Let λ\lambda be a nonempty partition into odd parts, let its largest part occur rr times, and write

π=φ(λ)=(π1>⋯>πk>0),πk+1=0,mj=πj−πj+1.\pi=\varphi(\lambda) =(\pi_1>\cdots>\pi_k>0), \qquad \pi_{k+1}=0, \qquad m_j=\pi_j-\pi_{j+1}.

By source Theorem 4.2, its lecture-hall length is

L=ℓh(π)=max⁡1≤j≤k(⌈πjmj⌉+j−1).L=\ell_h(\pi) = \max_{1\le j\le k} \left( \left\lceil\frac{\pi_j}{m_j}\right\rceil+j-1 \right).

Define the maximizing index set

I={j:⌈πjmj⌉+j−1=L}.I= \left\{ j: \left\lceil\frac{\pi_j}{m_j}\right\rceil+j-1=L \right\}.

For j∈Ij\in I, write uniquely

πj=(L−j)mj+rj,1≤rj≤mj.\pi_j=(L-j)m_j+r_j, \qquad 1\le r_j\le m_j.

The source defines the lecture-hall position by choosing a maximizing index with the largest rjr_j, resolving any remaining tie by the smallest index. Thus

rπ=max⁡j∈Irj.(1)r_\pi=\max_{j\in I}r_j. \tag{1}

Let τ\tau be the source's descent on odd partitions. Its gap-free coding sequence is

(bo(λ),bo(τλ),bo(τ2λ),…),\bigl( b_o(\lambda), b_o(\tau\lambda), b_o(\tau^2\lambda), \ldots \bigr),

and φ(λ)\varphi(\lambda) is the conjugate partition of that sequence. Applying τ\tau deletes its first entry, hence removes the first column of the conjugate:

φ(τsλ)=(π1−s,…,πk−s)>0=:π(s).(2)\varphi(\tau^s\lambda) = (\pi_1-s,\ldots,\pi_k-s)_{>0} =:\pi^{(s)}. \tag{2}

Source Theorem 7.6 proves, for every nonempty odd partition μ\mu,

g(μ)=2ℓh(φ(μ))−1,(3)g(\mu)=2\ell_h(\varphi(\mu))-1, \tag{3}

where g(μ)g(\mu) is its largest part. Each descent replaces exactly one occurrence of the current largest odd part tt by t−2t-2, or deletes one part if t=1t=1. Therefore the original largest part remains unchanged for exactly rr successive states. By (2)–(3),

r=min⁡{s≥1:ℓh(π(s))<L},(4)r= \min\{s\ge1:\ell_h(\pi^{(s)})<L\}, \tag{4}

with ℓh(∅)=0\ell_h(\varnothing)=0.

It remains to compute this first-drop time intrinsically. First L≥kL\ge k, since the contribution of j=kj=k is kk. Whenever jj remains nonterminal after subtracting ss, its gap is unchanged and its contribution is

Fj(s)=⌈πj−smj⌉+j−1.F_j(s) = \left\lceil\frac{\pi_j-s}{m_j}\right\rceil+j-1.

If j∈Ij\in I and j<kj<k, then

πj+1=(L−j−1)mj+rj≥rj.\pi_{j+1} = (L-j-1)m_j+r_j \ge r_j.

Thus for 0≤s<rj0\le s<r_j, the index remains nonterminal and

Fj(s)=L−1+⌈rj−smj⌉=L.F_j(s) = L-1+ \left\lceil\frac{r_j-s}{m_j}\right\rceil =L.

For s≥rjs\ge r_j, its contribution is at most L−1L-1 while nonterminal; if it becomes terminal, its contribution is j<Lj<L.

The index j=kj=k can belong to II only when L=kL=k, in which case rk=πkr_k=\pi_k. Its contribution remains LL precisely for s<rks<r_k and disappears afterward. An initially nonmaximizing index never becomes maximizing: its nonterminal contribution is nonincreasing, and a terminal contribution is j<Lj<L, unless j=k=Lj=k=L, which was already a maximizing index.

Consequently,

ℓh(π(s))=L⟺s<max⁡j∈Irj.\ell_h(\pi^{(s)})=L \quad\Longleftrightarrow\quad s<\max_{j\in I}r_j.

Combining this with (1) and (4) gives

r=rπ.\boxed{r=r_\pi.}

This proves Conjecture 8.2 for every odd partition, including partitions consisting entirely of ones.

Source: Wang and Zhang, Euler's partition theorem and lecture hall partition theorem, Conjecture 8.2, https://arxiv.org/abs/2607.16690.