The 5-cycle double cover conjecture

A kk-cycle double cover is a collection of at most kk Eulerian subgraphs such that every edge belongs to exactly two of them. A graph is bridgeless if it has no bridge.

5-cycle double cover conjecture. Every bridgeless graph has a 55-cycle double cover.

The result is a proposed improvement of the proved bound of eight Eulerian subgraphs. The conjecture is attributed in the source to Celmins and Preissmann and remains open there.

Equivalent formulations 2

Other statements of this same problem, merged from separate entries. Each is equivalent to the statement above — proving any one settles them all.

  1. 5-cycle-double-cover conjecture

    A cycle is a 2-regular graph, and a 5-cycle double cover of a graph GG is a set of five cycles such that every edge is in precisely two of them.

    5-cycle-double-cover conjecture. Every bridgeless graph has a 5-cycle double cover.

    The conjecture was stated independently by Celmins and Preissmann and is one of the principal cycle-cover problems for bridgeless graphs. The paper does not report a resolution.

    source: M. A. Fiol, G. Mazzuoccolo and E. Steffen, “On measures of edge-uncolorability of cubic graphs: A brief survey and some new results”, arXiv:1702.07156 (2017).

  2. The 5-cycle double cover conjecture

    A cycle is a subgraph in which every vertex has positive even degree. A 5-cycle double cover (55-CDC) of a graph GG is a collection of five cycles such that every edge belongs to exactly two of them. 5-cycle double cover conjecture. Every bridgeless graph GG admits a 55-CDC.

    The conjecture is a central problem in the theory of cycle covers. The paper uses it to derive bounds on the parameter T(G)T(G), but it remains open.

    source: Giuseppe Mazzuoccolo and Vahan Mkrtchyan, “Expanding vertices to triangles in cubic graphs”, arXiv:2504.19201 (2025).

Sources & referencesView supporting material

Primary source

Sang-il Oum, “A proof of the cycle double cover conjecture by OpenAI: An exposition”, arXiv:2607.16356 (2026).

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