A q-supercongruence for a truncated Appell series when n is 3 modulo 4

Let $n$ be a positive odd integer with $n\equiv 3\pmod{4}$, let $q$ be an indeterminate, and let $(a;q)_k$ denote the $q$-shifted factorial. Write $(a_1,a_2,\ldots,a_r;q)_k=\prod_{s=1}^r(a_s;q)_k$, and let $\Phi_n(q)$ denote the $n$th cyclotomic polynomial. The truncated Appell-series supercongruence.

$$\sum_{i=0}^{\frac{n-1}{2}}\sum_{j=0}^{\frac{n-1}{2}}\frac{(q;q^{2})_{i+j}(q;q^{2})_{i}(q;q^{2})_{j}(-q;q^{2})_{j}}{(q^2;q^2)_i^2(q^2;q^2)_j^2(-q^2;q^2)_j}q^{2i+2j}\equiv0\pmod{\Phi_{n}(q)^2}.$$

This is proposed on the basis of numerical evidence as a $q$-analogue of the first case of the paper's cited Appell-series result; its status is not resolved in the supplied text.