HypothesiX residue-pairing bound conjecture

For a squarefree integer QQ with 6Q6\mid Q, let UQU_Q be the set of residues rmodQr\bmod Q such that both rr and r+2r+2 are coprime to QQ. Define the residue-pairing bound

BQ(x)=rUQmin(π(x;Q,r),π(x;Q,r+2)),B_Q(x)=\sum_{r\in U_Q}\min\left(\pi(x;Q,r),\pi(x;Q,r+2)\right),

where

\pi(x;Q,a)=\\#\\{p\leq x:p\equiv a\pmod Q\\}.

Also let π2(x)\pi_2(x) denote the twin-prime counting function. HypothesiX's residue-pairing conjecture. For all x7x\geq 7 and every squarefree QQ with 6Q6\mid Q,

π2(x)BQ(x)+2.\pi_2(x)\leq B_Q(x)+2.

The conjecture is machine-generated and is described as nearly as difficult as the parity problem; only a weaker form is proved in the paper.

Sources & referencesView supporting material

Primary source

Madhuparna Das, “Mapping Mathematical Hardness: Machine-Assisted Conjecture Discovery and the Quantification of Non-Triviality”, arXiv:2606.14804 (2026).

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