Congruence conjecture for c(32n+23) modulo 8

From papers

Let c(n)c(n) denote the coefficient sequence under consideration, and let nN0n\in\mathbb{N}_0. The congruence conjecture for c(32n+23)c(32n+23).

c(32n+23)0 (mod8).c(32n+23)\equiv 0\ \left( \mathrm{mod} \, 8 \right).

This conjecture is proposed as an open question for future research. The authors report numerical verification for 32n+23500032n+23\le 5000, but no proof is supplied in the provided text.

Progress summary

Solved

A 2026 preprint claims to prove the conjecture, but the proof has not yet been independently verified.

Banerjee, Bringmann, and El Bachraoui proposed that c(32n+23)0(mod8)c(32n+23)\equiv0\pmod{8} for every nN0n\in\mathbb{N}_0. Their April 2026 paper reports numerical verification through 32n+23500032n+23\le5000 but labels the assertion Conjecture 8.1 and supplies no proof.

2026 preprint claiming a proof

Juejie Sun and Olivia X. M. Yao claim to prove a broader conjecture of Banerjee, Bringmann, and El Bachraoui; their stated infinite family includes the present congruence as the case k=1k=1. This is a claimed preprint proof, not an independently corroborated resolution in the retrieved material.

Current status (as of August 2026): The congruence is numerically verified and is covered by Sun–Yao's claimed 2026 preprint proof, but independent verification remains outstanding.

Sources
Sources & referencesView supporting material

Primary source

Koustav Banerjee, Kathrin Bringmann and Mohamed El Bachraoui, “On congruence conjectures of Andrews and Bachraoui”, arXiv:2604.02239 (2026).

Solutions 1

Proof

Prior proof and attribution. This conjecture was already proved by Sun and Yao in arXiv:2604.05403, Lemma 2.2, equation (2.22). The original problem is therefore not open. The proof below is only an alternative derivation through a stronger residue-three transfer identity; it does not claim the first proof.

The congruence follows from the stronger transfer identity

c(4m+3)pω(4m+3)(mod8)(m0),\boxed{ c(4m+3)\equiv-p_\omega(4m+3)\pmod8 \qquad(m\ge0), }

where the distinct mock-theta partition function pωp_\omega is defined by

qω(q)=N1pω(N)qN.q\omega(q)=\sum_{N\ge1}p_\omega(N)q^N.

The primary source gives

C(q)=N0c(N)qN=2qA(q)B(q)qω(q),C(q)=\sum_{N\ge0}c(N)q^N = 2qA(q)B(-q)-q\omega(-q),

and its equation (5.5) implies

A(q)A0(q4)+qA1(q4)(mod4),A1(q)2Z[[q]].A(q)\equiv A_0(q^4)+qA_1(q^4)\pmod4, \qquad A_1(q)\in2\mathbb Z[[q]].

Write B(q)=j=03qjBj(q4)B(q)=\sum_{j=0}^3q^jB_j(q^4). The exact published four-dissections of the same function BB are

B1(q)=2f28f17,B2(q)=4f22f44f15,fj=(qj;qj).B_1(q)=\frac{2f_2^8}{f_1^7}, \qquad B_2(q)=\frac{4f_2^2f_4^4}{f_1^5}, \qquad f_j=(q^j;q^j)_\infty.

Hence B12Z[[q]]B_1\in2\mathbb Z[[q]] and B24Z[[q]]B_2\in4\mathbb Z[[q]]. The residue-two part of A(q)B(q)A(q)B(-q) is therefore

A0B2A1B10(mod4).A_0B_2-A_1B_1\equiv0\pmod4.

The first term 2qA(q)B(q)2qA(q)B(-q) thus vanishes modulo 88 on every exponent 4m+34m+3, and the remaining term contributes

[q4m+2]ω(q)=pω(4m+3).-[q^{4m+2}]\omega(-q) = -p_\omega(4m+3).

This proves the transfer identity.

Theorem 1.1 of Andrews–Passary–Sellers–Yee gives

pω(22k+3n+174k+13)0(mod8)p_\omega\left( 2^{2k+3}n+\frac{17\cdot4^k+1}{3} \right)\equiv0\pmod8

for all k,n0k,n\ge0. Set k=1k=1, obtaining pω(32n+23)0(mod8)p_\omega(32n+23)\equiv0\pmod8. Since 32n+233(mod4)32n+23\equiv3\pmod4, the transfer identity yields

c(32n+23)0(mod8)(n0).\boxed{c(32n+23)\equiv0\pmod8\qquad(n\ge0).}

Sources: Banerjee–Bringmann–El Bachraoui, arXiv:2604.02239, equations (4.1), (5.5), Conjecture 8.1; Andrews–Passary–Sellers–Yee, The Ramanujan Journal 43 (2017), 347–357, Theorem 1.1, doi:10.1007/s11139-016-9812-2; “On second order mock theta function B(q)B(q),” Electronic Research Archive 30 (2022), 52–65, equations (1.6)–(1.7), doi:10.3934/era.2022003.

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