Deaconescu's solubility conjecture for finite groups with many elements of the same order
Let be a fixed positive integer and let be a finite group. Suppose that at least half of the elements of have order . Deaconescu's conjecture. Then is soluble. The paper shows that the original conjecture is false by giving counterexamples. For fixed , it holds when is a power of a prime other than or , and when or , but fails for many other values of , including all multiples of and greater than .
References
Primary source
Ryan McCulloch and Lee Tae Young, “Finite groups with many elements of the same order”, arXiv:2602.19340 (2026).
Progress summary
A 2026 preprint claims the conjecture is false in general, while proving it in several important special cases.
Deaconescu’s conjecture asserts that a finite group is soluble if at least half its elements have one fixed order. The 2026 preprint claims this unrestricted statement is false and identifies both surviving cases and broad families of counterexamples.
Known results
- Wall proved the assertion for involutions ().
- Liebeck and MacHale classified finite groups with at least half their elements of order .
- Mann and Berkovich obtained further structural and classification results for .
2026 arXiv preprint, version 2
The revised preprint claims the conjecture holds for , , , and every prime power with , but fails for every divisible by or , as well as some other . It further claims non-soluble examples with at least of elements of order , plus stronger quantitative bounds. These claims have no independent verification or published referee assessment in the retrieved sources.
Current status (as of September 2026): The unrestricted conjecture is claimed false, and the revised preprint claims complete classifications in several cases, but those claims remain unverified in the retrieved record.
Sources
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