The homology conjecture for total 3-cut complexes of complete graph–cycle products

Let KmK_m be the complete graph on mm vertices, let CnC_n be the cycle graph on nn vertices, and let Δ3t(KmCn)\Delta_{3}^t(K_m\square C_n) denote their total 33-cut complex. The total 3-cut cycle-product homology conjecture.

For m3m\geq3 and n=3n=3,

H~i(Δ3t(KmCn))={Z12(m23m+2),if i=mn6,0,otherwise.\widetilde{H}_i\bigl(\Delta_{3}^t(K_m\square C_n)\bigr)= \begin{cases} \mathbb{Z}^{\frac{1}{2}(m^2-3m+2)},&\text{if }i=mn-6,\\ 0,&\text{otherwise}. \end{cases}

For m2m\geq2 and n{4,5}n\in\{4,5\},

H~i(Δ3t(KmCn))={Zm12((m1)n2(m3)n2),if i=mn6,0,otherwise.\widetilde{H}_i\bigl(\Delta_{3}^t(K_m\square C_n)\bigr)= \begin{cases} \mathbb{Z}^{\frac{m-1}{2}((m-1)n^2-(m-3)n-2)},&\text{if }i=mn-6,\\ 0,&\text{otherwise}. \end{cases}

For m2m\geq2 and n6n\geq6,

H~i(Δ3t(KmCn))={Z12((m1)2n2(m24m+3)n+2),if i=mn6,0,otherwise.\widetilde{H}_i\bigl(\Delta_{3}^t(K_m\square C_n)\bigr)= \begin{cases} \mathbb{Z}^{\frac{1}{2}((m-1)^2n^2-(m^2-4m+3)n+2)},&\text{if }i=mn-6,\\ 0,&\text{otherwise}. \end{cases}

The conjecture is based on computed examples for total 33-cut complexes of complete graph–cycle products; the source does not provide a resolution.

Sources & referencesView supporting material

Primary source

Pratiksha Chauhan, Samir Shukla and Kumar Vinayak, “Total 2-cut complexes of powers of cycle graphs and Cartesian products of certain graphs”, arXiv:2512.04486 (2025).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.