Eigenvalue-weighted moment conjecture for holomorphic cusp forms

About 1 year old · traced to

Let ℓ≥1\ell\geq1 and r≥1r\geq1 be integers, and set

Xk(s)=Γ(12−s+k2)Γ(s−12+k2).X_k(s)=\frac{\Gamma\left(\frac{1}{2}-s+\frac{k}{2}\right)}{\Gamma\left(s-\frac{1}{2}+\frac{k}{2}\right)}.

For the forms f∈Hk(1)f\in H_k(1), let λf(ℓ)\lambda_f(\ell) denote the Hecke eigenvalue, let L(s,f)L(s,f) be the associated LL-function, and let L(s,sym⁡2f)L(s,\operatorname{sym}^2 f) be the symmetric-square LL-function. Define

G(ℓ;z1,…,zr)=A(ℓ;z1,…,zr)∏1≤i<j≤rζ(1+zi+zj),G(\ell;z_1,\ldots,z_r)=A(\ell;z_1,\ldots,z_r)\prod_{1\leq i<j\leq r}\zeta(1+z_i+z_j),

where AA is the absolutely convergent arithmetic factor defined in the source, and let Δ\Delta denote the Vandermonde determinant. Eigenvalue-weighted moment conjecture. There is a positive constant δ\delta such that

∑f∈Hk(1)2π2λf(ℓ)L(12,f)r(k−1)L(1,sym⁡2f)=Rk,r(ℓ)(1+O((ℓk)−δ+ε)),\sum_{f\in H_k(1)}\frac{2\pi^2\lambda_f(\ell)L\left(\frac{1}{2},f\right)^r}{(k-1)L(1,\operatorname{sym}^2 f)}=R_{k,r}(\ell)\left(1+O\left((\ell k)^{-\delta+\varepsilon}\right)\right),

where

Rk,r(ℓ)=(−1)r(r−1)/22rr!1(2πi)r∮⋯∮G(ℓ;z1,…,zr)Δ(z12,…,zr2)2z12r−1⋯zr2r−1∏j=1rXk(12+zj)−1/2 dz1⋯dzr.R_{k,r}(\ell)=\frac{(-1)^{r(r-1)/2}2^r}{r!}\frac{1}{(2\pi i)^r}\oint\cdots\oint\frac{G(\ell;z_1,\ldots,z_r)\Delta(z_1^2,\ldots,z_r^2)^2}{z_1^{2r-1}\cdots z_r^{2r-1}}\prod_{j=1}^rX_k\left(\frac{1}{2}+z_j\right)^{-1/2}\,dz_1\cdots dz_r.

The formula is a conjectural asymptotic for eigenvalue-weighted central moments, motivated by the recipe of Conrey, Farmer, Keating, Rubinstein and Snaith; its validity in the stated generality remains open.

References

Primary source

Zhining Wei, Liyang Yang and Shifan Zhao, “Low-lying zeros of Hilbert modular L-functions weighted by powers of central L-values”, arXiv:2508.18469 (2025).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.