Strict monotonicity of the equilibrium parameters in non-symmetric Showcase Showdown

About 1 year old · traced to

For each integer n>1n>1, let (ϵn,δn)(\epsilon_n,\delta_n) be the unique solution in [0,1]×[0,1][0,1]\times[0,1] of

{a)  (1+ex(−1+x))n−2=ey (−1+(1+ex (−1+y))n)+n exn ex (1+ey (−1+y)) (1+ex (−2+n+x)),b)  (1+ex(−1+x))n−1=e−x(nex(ex(y−1)+1)n−1+(ex(y−1)+1)n−1)ny.\left\{ \begin{aligned} \mathrm{a)}\;(1+e^{x}(-1+x))^{n-2}&= \dfrac{e^{y}\,\left( -1+{\left( 1+e^{x}\,\left( -1+y\right) \right) }^{n}\right) +n\,e^{x}}{n\,e^{x}\, \left( 1+e^{y }\,\left( -1+y\right) \right) \,\left( 1+e^{x}\,\left( -2+n+x\right) \right) },\\ \mathrm{b)}\;{(1+e^{x}(-1+x))}^{n-1}&=\frac{e^{-x} \left(n e^x \left(e^x (y-1)+1\right)^{n-1}+\left(e^x (y-1)+1\right)^n-1\right)}{n y}. \end{aligned} \right.

with δn>ϵn\delta_n>\epsilon_n. Strict-monotonicity conjecture. The sequences {ϵn}n>1\{\epsilon_n\}_{n>1} and {δn}n>1\{\delta_n\}_{n>1} are strictly increasing. The conjecture concerns the equilibrium parameters of the no-information, non-symmetric, constant-sum version of Showcase Showdown; the paper reports that the claim is suggested by computations for 2≤n≤62\leq n\leq 6 but does not provide a proof for every n>1n>1.

References

Primary source

L. Bayón, P. Fortuny ayuso, J. M. Grau, A. M. Oller-Marcén and M. M Ruíz, “Nash Equilibria in the Showcase Showdown game with unlimited spins”, arXiv:2504.08822 (2025).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.