The XZ conjecture for G2G_2

Let f:[0,1]6×T8Cf:[0,1]^6\times\mathbb{T}^8\to\mathbb{C} be an admissible function in the sense of the preceding definition, with spectrum Sp(f)\operatorname{Sp}(f). Let S(ξ1)S(\xi_1) denote the upper integration boundary and define

J~G2(x1,,x4,ξ1,ξ2):=ξ1ξ2[ξ12(16(1ξ22)3+9(1ξ22)24(1ξ22)2)(1ξ12)(3ξ24ξ22)2][ξ12(1ξ22)(1ξ12)ξ22]x1x2x3x4.\tilde{J}_{G_2}(x_1,\ldots,x_4,\xi_1,\xi_2):=\xi_1\xi_2\left[\xi_1^2\left(16(1-\xi_2^2)^3+9(1-\xi_2^2)-24(1-\xi_2^2)^2\right)-(1-\xi_1^2)(3\xi_2-4\xi_2^2)^2\right]\left[\xi_1^2(1-\xi_2^2)-(1-\xi_1^2)\xi_2^2\right]x_1x_2x_3x_4.

The XZ conjecture for G2G_2. If

T8[0,1]50S(ξ1)fPJ~G2dξ2dξ1dx1dx4dz1z1dz8z8=0\int_{\mathbb{T}^8}\int_{[0,1]^5}\int_0^{S(\xi_1)}f^P\tilde{J}_{G_2}\,d\xi_2\,d\xi_1\,dx_1\cdots dx_4\frac{dz_1}{z_1}\cdots\frac{dz_8}{z_8}=0

for all PNP\in\mathbb{N}, then 0\vec{0} does not lie in the convex hull of Sp(f)\operatorname{Sp}(f). The paper presents this as the remaining implication needed to obtain the Mathieu conjecture for G2G_2.

Sources & referencesView supporting material

Primary source

Kevin Zwart, “An addendum on the Mathieu Conjecture for SU(N), Sp(N) and G_2”, arXiv:2504.01516 (2025).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.