Border Comon's conjecture for minimal border rank

Let F(Cn)dF\in (\mathbb{C}^n)^{\otimes d} be a concise symmetric tensor of minimal border tensor rank, and let pFp_F be its corresponding polynomial. Here rk(F){\underline{{\bf rk}}}(F) denotes the border tensor rank of FF, and rkS(pF){\underline{{\bf rk}}}_S(p_F) denotes the symmetric border rank of pFp_F.

Border Comon's conjecture for minimal border rank. If

rk(F)=n,{\underline{{\bf rk}}}(F)=n,

then

rkS(pF)=rk(F).{\underline{{\bf rk}}}_S(p_F)={\underline{{\bf rk}}}(F).

This is the minimal-border-rank case of border Comon's conjecture, which asks whether border rank and symmetric border rank agree for symmetric tensors. The problem is largely open, although the paper establishes it for large classes of concise tensors, including all tame tensors and all tensors when nd+1n\leq d+1.

Sources & referencesView supporting material

Primary source

Tomasz Mańdziuk and Emanuele Ventura, “Symmetrization maps and minimal border rank Comon's conjecture”, arXiv:2411.05721 (2024).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.