The weighted Muckenhoupt conjecture for the Carleson–Dunkl operator

About 2 years old · traced to

Let α≥−1/2\alpha\geq -1/2, p∈(1,∞)p\in(1,\infty), and let w ⁣:R→[0,∞)w\colon\mathbb{R}\to[0,\infty) satisfy

sup⁡B(1∣B∣∫Bw(x)∣x∣2α+1 dx)(1∣B∣∫Bw(x)−p′/p∣x∣2α+1 dx)p/p′<∞,\sup_{B}\left(\frac{1}{|B|}\int_B w(x)|x|^{2\alpha+1}\,\mathrm{d}x\right)\left(\frac{1}{|B|}\int_B w(x)^{-p'/p}|x|^{2\alpha+1}\,\mathrm{d}x\right)^{p/p'}<\infty,

where the supremum is over all intervals B⊂RB\subset\mathbb{R} and 1/p+1/p′=11/p+1/p'=1. The weighted Carleson–Dunkl conjecture. Under this condition, there is a constant Cp,α,wC_{p,\alpha,w} such that

∥C∗αf∥Lp(R,w∣x∣2α+1 dx)≤Cp,α,w∥f∥Lp(R,w∣x∣2α+1 dx)\big\|\mathcal{C}_{\ast}^{\alpha}f\big\|_{L^p(\mathbb{R},w|x|^{2\alpha+1}\,\mathrm{d}x)}\leq C_{p,\alpha,w}\|f\|_{L^p(\mathbb{R},w|x|^{2\alpha+1}\,\mathrm{d}x)}

for every f∈Lp(R,w∣x∣2α+1 dx)f\in L^p(\mathbb{R},w|x|^{2\alpha+1}\,\mathrm{d}x). The preceding discussion shows that the known condition w∈Apαw\in A_p^\alpha is not optimal even when p=2p=2, motivating this Muckenhoupt-type condition with the measure ∣x∣2α+1 dx|x|^{2\alpha+1}\,\mathrm{d}x; whether it implies the weighted inequality remains open.

References

Primary source

Wojciech Słomian, “Oscillation inequalities for Carleson–Dunkl operator”, arXiv:2406.10896 (2025).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.